Answer
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By applying the Boyle's equation and substituting our given data the volume of the container was found to be 418.14 Litres
<h3>
Boyle's Law</h3>
Given Data
- number of moles of Ne = 5.1169 mol
We know that the relationship between pressure and temperature is given as
PV = nRT
R = 0.08206
Making the volume subject of formula we have
V= nRT/P
Substituting our given data to find the volume we have
V = 5.1169*0.08206*911/0.9148
V = 382.522353554/0.9148
V = 418.14 L
Learn more about Boyle's law here:
brainly.com/question/469270
Answer:
Alchemy is a practice of making gold from other metals.
Explanation:
Alchemy is a method which is practiced by the ancient scientists of Europe, Africa and Asia trying to produced gold from other metals. This method was failed to produced gold from metals and all scientist suggested that metals can not be converted into gold. Greeks were the people who presented the theory of alchemy in the first few centuries of CE.
The phosphate molecule that is released it is coupled to a different ADP molecule to make new molecule of ATP.
Hydrolysis of high-energy compound (ATP) using water:
ATP + H₂O → ADP + Pi
ATP is short for adenosine triphosphate.
Hydrolysis is a reaction that breaks down the chemical bonds between molecules via the addition of a water molecule.
A condensation reaction is a reaction that joins two molecules in a chemical bond.
ATP is resynthesized in a condensation reaction that adds an inorganic phosphate group to ADP. The addition of a phosphate group is catalyzed by the enzyme ATP synthase.
More about potential energy: brainly.com/question/21175118
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Answer is: 4.02 grams of water are required.
Chemical reaction: BaH₂ + 2H₂O → Ba(OH)₂ + 2H₂.
Ideal gas law: p·V = n·R·T.
p = 755 mm Hg ÷ 760.0 mmHg / atm = 0.993 atm.
T = 25 + 273.15 = 298.15 K.
V(H₂) = 5.50 L.
R = 0,08206 L·atm/mol·K.
n(H₂) = 0.993 atm · 5.5 L ÷ 0,08206 L·atm/mol·K · 298.15 K.
n(H₂) = 0.223 mol.
From chemical reaction: n(H₂O) : n(H₂) = 1 : 1.
n(H₂O) = 0.223 mol.
m(H₂O) = 0.223 mol · 18 g/mol.
m(H₂O) = 4.02 g.
