Answer:
Reagent A = 
Reagent B= 
Intermediate C= δ-Valerolactone
Explanation:
In the reaction from the alkene to the alcohol, we can use the <u>alkene hydration</u> in which the hydronium ion is added to the double bond followed by the attack of water to produce the <u>alcohol</u>.
Then in the conversion from alcohol to ketone can be produced if an <u>oxidant reactive</u><u> </u>is used. In this case the <u>Jones reagent </u>( ).
The intermediate is a structure produced by a <u>peroxyacid</u>. This reaction would introduce an <u>ester group </u>in the cycle generating the δ-Valerolactone (Figure 1).
Answer:
The answer to the question above is
The energy required to heat 87.1 g acetone from a solid at -154.0°C to a liquid at -42.0°C = 29.36 kJ
Explanation:
The given variables are
ΔHfus = 7.27 kJ/mol
Cliq = 2.16 J/g°C
Cgas = 1.29 J/g°C
Csol = 1.65 J/g°C
Tmelting = -95.0°C.
Initial temperature = -154.0°C
Final temperature = -42.0°C?
Mass of acetone = 87.1 g
Molar mass of acetone = 58.08 g/mol
Solution
Heat required to raise the temperature of solid acetone from -154 °C to -95 °C or 59 °C is given by
H = mCsolT = 87.1 g* 1.65 J/g°C* 59 °C = 8479.185 J
Heat required to melt the acetone at -95 °C = ΔHfus*number of moles =
But number of moles = mass÷(molar mass) = 87.1÷58.08 = 1.5
Heat required to melt the acetone at -95 °C =1.5 moles*7.27 kJ/mol = 10.905 kJ
The heat required to raise the temperature to -42 degrees is
H = m*Cliq*T = 87.1 g* 2.16 J/g°C * 53 °C = 9971.21 J
Total heat = 9971.21 J + 10.905 kJ + 8479.185 J = 29355.393 J = 29.36 kJ
The energy required to heat 87.1 g acetone from a solid at -154.0°C to a liquid at -42.0°C is 29.36 kJ
Answer:
a, d and e. are true.
Explanation:
The reaction that occurs is:
Na2CO3(aq) + CaCl2(aq) → CaCO3(s) + 2NaCl
In ideal conditions, the percent yield of the reaction must be 100%. All explanations about why the student could not collect all precipitate are right:
a. The combined reactants were not stirred before filtering the precipitate. Not stirring could not promote all the reaction. <em>TRUE.</em>
b. The student did not completely dry the precipitate before weighing it. If the student don't dry the precipitate, the mass of precipitate must be higher producing a percent yield > 100%. <em>FALSE.</em>
c. The precipitate was not washed prior to drying. Produce more mass. <em>FALSE.</em>
d. A rubber policeman was not used to scrape precipitate from the beaker. If the student doesn't collect all the precipitate the percent yield could be < 100%.. <em>TRUE.</em>
e. The filter paper was not wetted with water prior to filtering the precipitate. <em>TRUE. </em>If you don't wet the filter paper you can lose a part of precipitate from the walls of this one.
They have similar properties.Bromine and Chlorine both have equal chemical properties. They both have 7.electrons in the outermost energy level. They both gain 1 electron to get the. noble gas configuration.Cl and Br have same chemical properties. They have 7,valence electrons. They both are non-metals. Bromine and chlorine are in group VII A, which could also be designated Group 7a, of the narrow form periodic table that was commonly used before 1980. Most chemists now prefer a wide form periodic table, in which these elements are in column 17. The periodic table has been set up to illustrate the repeating nature of the elements as we progress along their atomic number. Cl (chlorine) and Br (bromine) are very similar because they both have seven valence electrons, and both need only one more to be like a noble gas. (The need to have eightelectrons in the outer main shell is called the octet rule, and the reason for <span>this is understood by scientists, but is complicated.) HOPE IT HELPED
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