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3 years ago

Write a real-world problem that can be represented by the equation 1/2x+6=20. Then solve the problem

1 answer:

8 0

One-half of a number plus six will equal 20.

Solving:
1/2x + 6 = 20
-6 -6
1/2x = 14
*2/1 *2/1
x = 28 <--Answer to problem

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Mansa runs 1/3 of a mile in 1/16 of an hour. what is his unit rate in miles per hour

REY [17]

Answer:

5 1/3 mph or 5.33mph

Step-by-step explanation:

1/3 of a mile / 1/16 of an hour = MPH. In order to divide fractions you flip the bottom fraction and multiply across. 1/3 / 1/16 = 1/3 * 16/1 = 16/3 = 5 1/3 = 5.33mph

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3 years ago

What is 2 x 2 ? Plz say fast Hehe

gogolik [260]

Answer:

It is 5*5*4/25

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3 years ago

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Find the mean deviation from each data set. (a) 12 6 7 3 15 10 18 5

Pavlova-9 [17]

Answer:

Step-by-step explanation:

you find the mean of the numbers and use the mean and subtract the mean from all of the numbers.

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3 years ago

Add 15 3/5 and 21 4/5 as a mixed number please help

Reptile [31]

Answer:

15(5)+3=78

21(5)+4=109

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Step-by-step explanation:

7 0

3 years ago

Please help!

777dan777 [17]

Answer:

$\begin{array}{ccc}\text{Radius}&\text{Volume of sphere}&\text{Volume of cylinder}\\&&\\1&\dfrac{4}{3}\pi &2\pi \\&&\\2&\dfrac{32}{3}\pi &16\pi \\&&\\3&36\pi &54\pi \\&&\\4&\dfrac{256}{3}\pi &128\pi \\&&\\5&\dfrac{500}{3}\pi &250\pi\end{array}$

Step-by-step explanation:

Use formulas for the volumes:

$V_{sphere}=\dfrac{4}{3}\pi r^3,\\ \\V_{cylinder}=\pi r^2h=\pi r^2\cdot 2r=2\pi r^3.$

1. When r=1,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 1^3=\dfrac{4}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 1^3=2\pi.$

2. When r=2,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 2^3=\dfrac{32}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 2^3=16\pi.$

3. When r=3,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 3^3=36\pi,\\ \\V_{cylinder}=2\pi \cdot 3^3=54\pi.$

4. When r=4,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 4^3=\dfrac{256}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 4^3=128\pi.$

5. When r=5,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 5^3=\dfrac{500}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 5^3=250\pi.$

Note that for all r,

$\dfrac{V_{sphere}}{V_{cylinder}}=\dfrac{\frac{4}{3}\pi r^3}{2\pi r^3}=\dfrac{2}{3}.$

8 0

3 years ago

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