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miv72 [106K]
3 years ago
8

What is 1 Oz equal to in grams?

Chemistry
2 answers:
lakkis [162]3 years ago
4 0
1 Oz is 28.3495 grams

hope this helps!
pentagon [3]3 years ago
3 0

Conversion factor for ounces and grams.

<em>1 ounce is equal to approximately 28.4 grams. </em>

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How do I solve this problem?
JulijaS [17]
First question. Applying ideal gas equation PV=nRT, P= 101.3 x 10³Pa = 1atm. therefore, 1 x 260 x 10^-3 = n x 0.082 x 294.( Temperature in kelvin=273+21). n = 0.01 moles. Volume of gas at STP= n x 22.4 = 0.01x22.4 = 0.224L. Hope this helps
5 0
3 years ago
Scientists call an organism that has two diferente alleles for a trait
aleksklad [387]
An organism that has two different alleles for a trait is called heterogeneous
8 0
3 years ago
Boron sulfide, B2S3(s), reacts violently with water to form dissolved boric acid (H3BO3) and hydrogen sulfide gas
Gwar [14]

The equation structure for the above mentioned reaction can be written as  

B_{2} S_{3}+6 H_{2} O \rightarrow 2 H_{3} B O_{3}+3 H_{2} S \uparrow

<u>Explanation:</u>

Considering the above reaction, When Boron sulfide, reacts with water more violently to form boric acid and hydrogen sulfide gas.

B_{2} S_{3}+H_{2} O \rightarrow H_{3} B O_{3}+H_{2} S \uparrow

In order to balance the equation, we can do as follows.There are 2 B - atoms on both sides of the equation, but only 2 H - atoms, and one O - atom on LHS, so we have to balance it by putting 6 in front of water and 2 in front of Boric acid and 3 in front of hydrogen sulphide gas, so that we have 2 B - atoms, 3 - S atoms, 12 H - atoms on both sides of the equation, and it is balanced. Balanced equation is given as,

B_{2} S_{3}+6 H_{2} O \rightarrow 2 H_{3} B O_{3}+3 H_{2} S \uparrow

Thus a Balanced equation of the above mentioned reaction is written.

8 0
3 years ago
Final volume of Argon gas:
DerKrebs [107]

Answer:

6.78 × 10⁻³ L

Explanation:

Step 1: Write the balanced equation

Mg₃N₂(s) + 3 H₂O(g) ⇒ 3 MgO(s) + 2 NH₃(g)

Step 2: Calculate the moles corresponding to 10.2 mL (0.0102 L) of H₂O(g)

At STP, 1 mole of H₂O(g) has a volume of 22.4 L.

0.0102 L × 1 mol/22.4 L = 4.55 × 10⁻⁴ mol

Step 3: Calculate the moles of NH₃(g) formed from 4.55 × 10⁻⁴ moles of H₂O(g)

The molar ratio of H₂O to NH₃ is 3:2. The moles of NH₃ produced are 2/3 × 4.55 × 10⁻⁴ mol = 3.03 × 10⁻⁴ mol.

Step 4: Calculate the volume corresponding to 3.03 × 10⁻⁴ moles of NH₃

At STP, 1 mole of NH₃(g) has a volume of 22.4 L.

3.03 × 10⁻⁴ mol × 22.4 L/mol = 6.78 × 10⁻³ L

3 0
3 years ago
In which direction did the following equilibrium shift when it was placed in the hot water bath? [CoCl4] 2- (aq) + 6H2O (l) ⇌ [C
djyliett [7]

Answer:

The equilibrium position will shift towards the lefthand side.

Explanation:

[CoCl4] 2- (aq) + 6H2O (l) ⇌ [Co(H2O)6] 2+ (aq) + 4 Cl- (aq)

The equation written above in exothermic as written. That is, the forward reaction is exothermic. The equilibrium position is observable by monitoring the colour change of the solution. At the left hand side, the solution is blue but at the right hand side the solution is pink. Addition of heat (in a hot water bath) will shift the equilibrium towards the left hand side, that is formation of more [CoCl4] 2- making the solution to appear blue in colour.

3 0
4 years ago
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