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svetlana [45]
3 years ago
10

Need the ionic formula

Chemistry
1 answer:
JulijaS [17]3 years ago
3 0

Answer:

To find the formula of an ionic compound, first identify the cation and write down its symbol and charge. Then, identify the anion and write down its symbol and charge. Finally, combine the two ions to form an electrically neutral compound.

Explanation:

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(b) A compound X contains carbon, hydrogen and oxygen only
faust18 [17]

Answer:

C2H4O

Explanation:

C H O

54.54/12 9.09/1 36.37/16

4.545 9.09 2.27

4.545/2.27 9.09/2.27 2.27/2.27

2.00 4.00 1

Empirical formula is C2H4O

3 0
3 years ago
66.0g of dry ice (solid carbon dioxide)
d1i1m1o1n [39]

Answer:

Dry Ice is frozen CO2

Explanation:

we just need to convert the 10g into moles

Carbon has atomic mass of 12, and oxygen has atomic mass of 16, so molar mass = 12 + 16(2)= 44

Do  66/44 to get the moles = 1.5 (ans)

3 0
3 years ago
Calculate the amount of heat needed to convert 50.0 g of liquid water at to steam at 100ºC.
Kipish [7]

Answer:

We need 113000 J of heat (option 2 is correct)

Explanation:

Step 1: Data given

Mass of liquid water = 50.0 grams

ΔHVap = 2260 J/g

Temperature = 100 °C

ΔHVap = The amount of heat released to change phase of a liquid water to steam = 2260 J/g

Step 2: Calculate the heat needed

Q =m* ΔHVap

⇒with Q = the amount of heat needed = TO BE DETERMINED

⇒with m = the mass of water = 50.0 grams

⇒with ΔHVap = 2260 J/g

Q = 50.0 grams * 2260 J

Q = 113000 J

We need 113000 J of heat (option 2 is correct)

6 0
3 years ago
PLEASE HELP...<br> 22 POINTS. ONLY IF YOU KNOW YOUR ANSWER IS RIGHT PLEASE
Harman [31]
Cellular respiration! (A)
7 0
3 years ago
Sabiendo que a 20 °C, 0,275 moles de una sustancia desconocida cuya densidad
dimulka [17.4K]

Answer:

a) M=154.224g/mol

b) moleculas=4.33x10^{23}moleculas

c) m=2.56x10^{-22}g

Explanation:

Hola.

Para resolver los numerales a), b) y c), debemos seguir los siguientes procedimientos:

a) En este caso, primeo calculamos la masa que 45.9 cm³ ocupan con una densidad 0.924 g/cm³ como se muestra a continuación:

\rho=\frac{m}{V}\\ \\m=\rho V =0.924\frac{g}{cm^3}*45.9cm^3=42.4g

Seguidamente, sabiendo que estos gramos ocupan 0.275 moles, podemos facilmente calcular la masa molar como la relación entre ellas:

M=\frac{m}{n}=\frac{42.4g}{0.275mol}\\  \\M=154.224g/mol

b) En este caso, como se tienen 120 cm³ calculamos la nueva masa:

m=0.924\frac{g}{cm^3} *120cm^3=110.88g

Luego, con la masa molar, las moles:

n=110.88g*\frac{1mol}{154.224g} =0.719mol

Finalmente, con el número de Avogadro, las moléculas presentes:

moleculas=0.719mol*\frac{6.022x10^{23}moleculas}{1mol} \\\\moleculas=4.33x10^{23}moleculas

c) Aquí, consideramos que hay una molécula de la sustancia, por lo que usando el número de Avogadro, podemos calcular las moles que una molécula tiene:

n=1molecula*\frac{1mol}{6.022x10^{23}moleculas}=1.66x10^{-24}mol

Luego, usando la masa molar, calculamos la masa de una molécula:

m=1.66x10^{-24}mol*\frac{154.224g}{1mol} \\\\m=2.56x10^{-22}g

¡Saludos!

5 0
3 years ago
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