All categories

4 years ago

If a material has a high thermal conductivity, is it a conductor or an insulator?

Physics

1 answer:

____ [38]4 years ago

3 0

Answer:

If a material has high thermal conductivity, it is a conductor.

If a material has low thermal conductivity, it is an insulator.

You might be interested in

According to the Hooke’s law formula, the force is proportional to what measurement?

vesna_86 [32]

According to Hooke's Law formula. The force is proportional to the displacement of the spring. I believe

8 0

3 years ago

Read 2 more answers

Savanna regions developed during the Triassic period.

stich3 [128]

The answer is : true

5 0

1 year ago

Two stones, one with twice the mass of the other, are thrown straight up and rise to the same height h. Compare their changes in

Lady bird [3.3K]

<h2>The gravitational potential energy is double for stone with twice the mass of other stone.</h2>

Explanation:

Let mass of stone 1 be m.

Mass of stone 2 is twice the mass of stone 1.

Mass of stone 2 = 2m

We know that

Gravitational potential energy = Mass x acceleration due to gravity x Height

PE = mgh

For stone 1 ,

PE₁ = mgh

For stone 2 ,

PE₂ = 2mgh = 2 PE₁

So the gravitational potential energy is double for stone with twice the mass of other stone.

4 0

3 years ago

Read 2 more answers

At time t=0 a positively charged particle of mass m=3.57 g and charge q=9.12 µC is injected into the region of the uniform magne

larisa [96]

Answer:

10.78 s

Explanation:

The force on the charge is computed by using the equation:

$F^{\to}= qE^{\to} +q (v^{\to} + B^{\to}) \\ \\ F^{\to} = (9.12 \times 10^{-6}) *278 (-\hat k) +9.12 *10^{-6} *2.1 *0.18 (\hat i * \hat k) \\ \\ F^{\to} = -2.535 *10^{-3} \hat k -3.447*10^{-6} \hat j$

F = ma

∴

$a ^{\to}= \dfrac{F^{\to}}{m}$

$a ^{\to}= \dfrac{-1}{3.57\times 10^{-3}}(2.535*10^{-3}\hat k + 3.447*10^{-6} \hat j)$

$a ^{\to}=-0.710 \hat k -9.656*10^{-4} \hat j$

At time t(sec; the partiCle velocity becomes $v(t) = 3.78 v_o$

The velocity of the charge after the time t(sec) is expressed by using the formula:

$v^{\to}= v_{o \ \hat i} + a^{\to }t \\ \\ \implies (2.1)\hat i -0.710 t \hat k -9.656 \times 10^{-4} t \hat j = 3.78 v_o \\ \\ \implies (2.1)^2 +(0.710\ t)^2+ (9.656 *10^{-4}t )^2 = (3.78 *2.1^2 \\ \\ \implies 4.41 +0.5041 t^2 +9.324*10^{-7} t^2 = 63.012 \\ \\ \implies 4.41 +0.5041 t^2 = 63.012\\ \\ 0.5041t^2 = 63.012-4.41 \\ \\ t^2 = \dfrac{58.602}{0.5041} \\ \\ t^2 = 116.25 \\ \\ t = \sqrt{116.25} \\ \\ \mathbf{t = 10.78 \ s}$

8 0

3 years ago

Calculate the equivalent resistance

Whitepunk [10]

Not enough information

8 0

3 years ago