Answer:
the frequency of this mode of vibration is 138.87 Hz
Explanation:
Given;
length of the copper wire, L = 1 m
mass per unit length of the copper wire, μ = 0.0014 kg/m
tension on the wire, T = 27 N
number of segments, n = 2
The frequency of this mode of vibration is calculated as;

Therefore, the frequency of this mode of vibration is 138.87 Hz
It becomes a positive Iron
Answer: A. 24,000,000,000 km
Explanation: An Astronomical Unit commonly abbreviated as AU is the average distance between Earth and the Sun and is about 150 million kilometers.
Astronomical unit is mainly used to measure distances within our solar system.
1 AU is equal to
km
Thus 160 AU is equal to 
Answer:
8
Explanation:
(8√2)² = x² + x²
8² × √2² = 2x²
64 × 2 = 2x²
128 = 2x²
64 = x²
x = 8
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We will have that the graph that describes the scenario is given by graph B.