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ICE Princess25 [194]
3 years ago
5

Three examples of each of Newton's Law 1st 2nd and 3rd

Physics
1 answer:
erik [133]3 years ago
8 0

<em>Newton's 2nd Law </em><em> The second law of motion states that acceleration is produced when an unbalanced force acts on an object (mass). ... Newton's 3rd Law The third law of motion sates that for every action there is a an equal and opposite reaction that acts with the same momentum and the opposite velocity.</em>

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How many lines per mm are there in the diffraction grating if the second order principal maximum for a light of wavelength 536 n
grandymaker [24]

To solve this problem it is necessary to apply the concepts related to the principle of superposition and the equations of destructive and constructive interference.

Constructive interference can be defined as

dSin\theta = m\lambda

Where

m= Any integer which represent the number of repetition of spectrum

\lambda= Wavelength

d = Distance between the slits.

\theta= Angle between the difraccion paterns and the source of light

Re-arrange to find the distance between the slits we have,

d = \frac{m\lambda}{sin\theta }

d = \frac{2*536*10^{-9}}{sin(24)}

d = 2.63*10^{-6}m

Therefore the number of lines per millimeter would be given as

\frac{1}{d} = \frac{1}{2.63*10^{-6} }

\frac{1}{d} = 379418.5\frac{lines}{m}(\frac{10^{-3}m}{1 mm})

\frac{1}{d} = 379.4 lines/mm

Therefore the number of the lines from the grating to the center of the diffraction pattern are 380lines per mm

6 0
3 years ago
PLEASE HELP ME A lens with a surface that curves outward like the exterior of a sphere is __________. (Points : 1) reflected ref
yanalaym [24]
Convex.

Concave curved inward (like how a cave foes in) and convex curves outward. Reflected and refracted do not apply to a lens.
3 0
3 years ago
Read 2 more answers
The charge of an electron is
AlladinOne [14]
Proton positive; electron negative; neutron no charge<span>. </span>The charge<span> on the proton and </span>electron<span> are exactly the same size but opposite. The same number of protons and </span>electrons<span> exactly cancel one another in a neutral atom.
</span> 
hoped it helped
6 0
3 years ago
Please help help me please
vodomira [7]
The answer is either c or d but c is the best answer
4 0
3 years ago
A dragster takes off from rest and crosses the finish line 320 m away. If the dragster is able to accelerate at 10LaTeX: \frac{m
Rasek [7]

Answer:

t = 8 s

Explanation:

In order to find the time taken by the dragster we will use equations of motion. Here, we will use second equation of motion:

s = Vi t + (1/2)at²

where,

s = distance covered = 320 m

Vi = Initial Velocity = 0 m/s (Since, dragster starts from rest)

t = time taken = ?

a = acceleration of dragster = 10 m/s²

Therefore,

320 m = (0 m/s)t + (1/2)(10 m/s²)t²

t² = (320 m)(2)/(10 m/s²)

t = √(64 s²)

<u>t = 8 s</u>

3 0
3 years ago
Read 2 more answers
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