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2 years ago

When describing image formation in mirrors, what is the angle of incidence?

2 answers:

5 0

'B' is the correct choice.

BUT ... the angle of incidence is not the angle between the light ray
and the mirror. It's the angle between the light ray and the NORMAL
to the mirror. The 'normal' is the line that's perpendicular to the mirror.

Eva8 [605]2 years ago

5 0

Answer:

B. The angle the light ray makes as it strikes the surface.

Explanation:

Angle of the incidence is the angle that incident light ray will make with the normal to the surface at which light will strike. The surface is reflecting surface and here it follow the law of reflection

As per law of reflection of light angle of incidence with respect to the normal must be equal to the angle of reflection with normal in other direction.

So we can say that

angle of incidence = angle of reflection

so here we can say that the correct answer would be

B. The angle the light ray makes as it strikes the surface.

so the light ray will reflect at the same angle as that of angle of incidence given in it

so it must be

$\theta_i = \theta_r$

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A blackbody curve relates _____. intensity of radiation to energy intensity of radiation to wavelength wavelength to energy surf

neonofarm [45]

A blackbody curve represents the relation between <u>intensity of radiation with wavelength.</u>

Here in this curve we can see that all ideal blackbody radiates almost all wavelength of radiations and these radiations are of different intensity.

here intensity will be maximum for a given wavelength of radiation and the relation of this wavelength with the temperature of the object is given by Wein's law

It is given by

$\lambda = \frac{b}{T}$

now if we increase the temperature the maximum intensity for which wavelength is given will shift to the left.

Using this all we can also compare the temperature of two blackbody for which radiation graph is given to us.

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3 years ago

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lesya692 [45]

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3 years ago

If the depth of water in a well is 10m, what is the pressure exerted by it the bottom of the well ? ( Use g = 10 m/s2)

Tasya [4]

Answer:

The precise answer depends on the density and therefore the temperature of the water, but we can obtain a reasonable approximation by assuming that the density of the water is 1000 kilograms per cubic meter (kg/m³).

Since the depth of the water in the well is 10 m, the volume of water directly above an area A of a square meters (m²) at the bottom of the well is 10×a m³.

Since the density of the water is 1,000 kg/m³, the mass of water directly above area A is (1,000 kg/m³) × (10×a m³) = (1000×10×a kg) = 10,000×a kg.

Since g = 9.8 m/s², the force of gravity acting on the water directly above area A is (9.8 m/s²) × (10,000×a kg) = 9.8×10,000×a N (newtons) = 98,000×a N.

So the pressure of water acting on area A is (98,000×a N)/(a m²) = (98,000×a)/a N/m² = 98,000 pascals (pa). And since A could be any given area at the bottom of the well, this is the pressure at any point at the bottom of the well.

So the pressure at the bottom of the well is 98,000 pascals (or 98,000/101,325 standard atmospheres = 560/579 atmospheres ~ 0.967 standard atmospheres).

Please comment below if you have any questions.

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2 years ago

Which provides the best analogy for an electron in an atomic orbital?

Svetllana [295]

<h2>Answer: a bee trying to escape from a closed jar </h2>

In an atom the electrons will occupy orbitals so that their energy is as small as possible. That is why the orbitals are ordered based on their energy level in an increasing order, which is associated with a particular range of energy based on its distance from the atom nucleus.

In this sense, an electron "jumps" from one level to another in the atom in the same way a bee tries to escape from a closed jar.

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2 years ago

In which medium would sound travel the fastest? a)across a room b)in a swimming pool c)through outer space d)through a railroad

lora16 [44]

d)through a railroad track

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3 years ago