All categories

2 years ago

When describing image formation in mirrors, what is the angle of incidence?

2 answers:

5 0

'B' is the correct choice.

BUT ... the angle of incidence is not the angle between the light ray
and the mirror. It's the angle between the light ray and the NORMAL
to the mirror. The 'normal' is the line that's perpendicular to the mirror.

Eva8 [605]2 years ago

5 0

Answer:

B. The angle the light ray makes as it strikes the surface.

Explanation:

Angle of the incidence is the angle that incident light ray will make with the normal to the surface at which light will strike. The surface is reflecting surface and here it follow the law of reflection

As per law of reflection of light angle of incidence with respect to the normal must be equal to the angle of reflection with normal in other direction.

So we can say that

angle of incidence = angle of reflection

so here we can say that the correct answer would be

B. The angle the light ray makes as it strikes the surface.

so the light ray will reflect at the same angle as that of angle of incidence given in it

so it must be

$\theta_i = \theta_r$

You might be interested in

How do the discovery of gravity and the invention of electronic satellites most likely relate to the processes of scientific inv

Leya [2.2K]

Answer:

Explanation:

because i said so

5 0

2 years ago

A meteoroid is in a circular orbit 600 km above the surface of a distant planet. The planet has the same mass as Earth but has a

AVprozaik [17]

<h2>Answer:</h2><h2>The acceleration of the meteoroid due to the gravitational force exerted by the planet = 12.12 m/ $s^{2}$ </h2>

Explanation:

A meteoroid is in a circular orbit 600 km above the surface of a distant planet.

Mass of the planet = mass of earth = 5.972 x $10^{24}$ Kg

Radius of the earth = 90% of earth radius = 90% 6370 = 5733 km

The acceleration of the meteoroid due to the gravitational force exerted by the planet = ?

By formula, g = $\frac{GM}{r^{2} }$

where g is the acceleration due to the gravity

G is the universal gravitational constant = 6.67 x $10^{-11}$ $m^{3} kg^{-1} s^{-2}$

M is the mass of the planet

r is the radius of the planet

Substituting the values, we get

g = $\frac{(6.67 * 10^{-11}) (5.972 * 10^{24}) }{5733^{2} }$

g = 12.12 m/ $s^{2}$

The acceleration of the meteoroid due to the gravitational force exerted by the planet = 12.12 m/ $s^{2}$

6 0

3 years ago

1. boiling point of water

melomori [17]

Answer:

what is the question. . .

5 0

2 years ago

Two parallel plates are 1 cm apart and are connected to a 500 V source. What force will be exerted on a single electron half way

VladimirAG [237]

Answer: 8*10^-15 N

Explanation: In order to calculate the force applied on an electron in the middle of the two planes at 500 V we know that, F=q*E

The electric field between the plates is given by:

E = ΔV/d = 500 V/0.01 m=5*10^3 N/C

the force applied to the electron is: F=e*E=8*10^-15 N

3 0

2 years ago

Which three quantities can be used to calculate acceleration?

PtichkaEL [24]

D is the correct answer, assuming that this is the special case of classical kinematics at constant acceleration. You can use the equation V = Vo + at, where Vo is the initial velocity, V is the final velocity, and t is the time elapsed. In D, all three of these values are given, so you simply solve for a, the acceleration.
A and C are clearly incorrect, as mass and force (in terms of projectile motion) have no effect on an object's motion. B is incorrect because it is not useful to know the position or distance traveled, unless it will help you find displacement. Even then, you would not have enough information to use a kinematics equation to find a.

4 0

3 years ago