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lianna [129]
2 years ago
13

Out of a pair of identical springs of force constants, 240Nm-1 one is compressed by 10 cm and the other is stretched by 10 cm. W

hat is the difference in the potential energies stored in the two springs?​
Don't spam ❌
Physics
2 answers:
Nadusha1986 [10]2 years ago
6 0

Explanation:

<h3>Answer is zero</h3>

The stored potential energy of a spring is independent whether it is compressed or expanded

This doesn't depend upon movement in left from natural length or right.

This is because the spring always does negative work and opposite to the direction of motion.

<h3>Mathematically AlsoP=\sf \orange{  \frac{1}{2} kx^2}</h3>

<h3>-XxItzAdiXx</h3>
rosijanka [135]2 years ago
3 0

Answer:

U=1/2kx²

U1=1/2×240×(-10/100)²

U2=1/2×240×(10/100)²

difference, ️U=U1-U2=0

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What is called the process of finding exact quantity of a substance?​
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Answer:

Measurement is called the process of finding exact quantity of a substances.

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2 years ago
Compare the inner core and the outer core?
vfiekz [6]

To compare the inner core and the outer core, we need to outline the parameters based on

  1. Temperature - the outer core has 2000-5000 C, while inner reach 6000 C
  2. Structure and consistency - The outer core consist of iron and nickel, mix with low amount of gold, platinum, and uranium, while inner is the melting pot of all dense material and lot of uranium.
  3. Depth - The outer core has depth to 2900 km, while inner core has 1300 - 1400 km radius.

<h3>Further explanation</h3><h3>Consistency / materials</h3>
  • Both the outer core and the inner core are made generally of iron and nickel.  
<h3 /><h3>Temperature</h3>
  • The outer core achieves a temperature of 2000°c. The inward center has a temperature as high as 5000°c.
  • The inner core achieves a temperature of 6000 °c.
  • Within this temperature, both nickel and iron are dissolved and converted into a fluid.

<h3>Structure</h3>
  • In contrast to the outer core, the internal base is reduced in spite of the boiling temperature achieved the radioactive rot of uranium due to the incredible weight that keeps this layer in a stable stage.
  • The layer that partitions the external center and internal center is known as Bullen brokenness. Bullen brokenness is likewise the most sizzling locale of wherein the temperature reaches up to 6000°c its as hot as the outside of the sun.

<h3>Depth </h3>
  • Outside the outer and inner core, there is mantle that has the depth to around 2,900 kilometers from the Earth's surface.
  • The outer has depth more than 2900 kilometers from Earth surface.
  • The iner core is the deepest among all of them and has radius for 1300 kilometers.
  • Check the structure of earth here brainly.com/question/2162876

<h3>Structure of Earth</h3>

The Earth is separated into four layers. The external layer is the hull, beneath the covering is the mantle, and pursued by the external center, at that point, the most profound and the most smoking layer is known as the internal center.

<h3>Learn more</h3>

Here are the four layers of the Earth

  1. Hull
  2. Mantle
  3. External center
  4. Internal center

<h3>1. Hull or crust </h3>

The hull is the peripheral and the thinnest layer which goes about as the skin of the Earth that stretches out from the surface to around 32 kilometers beneath. This is the layer where we live, and volcanoes, quake, and mountain reaches are framed.

  • The marine shell is denser and more slender contrasted with mainland hull.
  • Mainland hull is thicker and is less thick contrasted with the maritime shell.

<h3>2. Mantle </h3>

Underneath the outside is the layer known as the mantle, which stretches out to around 2,900 kilometers from the Earth's surface. The coat is the thickest layer of the Earth and is progressively thick contrasted with the outside. It is the path more sizzling than the covering and equipped for liquefying it. The upper mantle is plastic, its made up of magma that as a result of an excessive amount of warmth it streams which causes changes on the outside of the Earth.

<h3>3. Outer Core </h3>

The external center is 2900 kilometers underneath the outside of the Earth. It is for the most part comprised of iron and nickel; however, in the fluid stage and its temperature ranges to about 2000°C. Regardless of whether the external center has a high weight, yet because of its a lot higher temperature, nickel and iron are liquefied. The external center is streaming outside the internal center, which produces an attractive field that shields the Earth from the hazardous, radioactive material originating from the warmth of the sun.

<h3>4. Internal Core </h3>

The internal center is the most profound layer comprised of heavy iron and nickel and has a sweep of around 1,300 kilometers. Its temperature scopes to about 5000°C. The internal has the most elevated thickness contrasted with the other. The warmth in the inside of the Earth is brought about by the radioactive rot of uranium in the internal center, which discharges considerable measure of heat.

Perhaps you are interested within the topic of

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<h3>Core Curriculum category</h3>

Subject : Geography

Class : 8

Subchapter : Earth and its structure.

4 0
3 years ago
Read 2 more answers
A freshly prepared sample of radioactive isotope has an activity of 10 mCi. After 4 hours, its activity is 8 mCi. Find: (a) the
Maurinko [17]

Answer:

(a). The decay constant is 1.55\times10^{-5}\ s^{-1}

The half life is 11.3 hr.

(b). The value of N₀ is 2.38\times10^{11}\ nuclei

(c). The sample's activity is 1.87 mCi.

Explanation:

Given that,

Activity R_{0}=10\ mCi

Time t_{1}=4\ hours

Activity R= 8 mCi

(a). We need to calculate the decay constant

Using formula of activity

R=R_{0}e^{-\lambda t}

\lambda=\dfrac{1}{t}ln(\dfrac{R_{0}}{R})

Put the value into the formula

\lambda=\dfrac{1}{4\times3600}ln(\dfrac{10}{8})

\lambda=0.0000154\ s^{-1}

\lambda=1.55\times10^{-5}\ s^{-1}

We need to calculate the half life

Using formula of half life

T_{\dfrac{1}{2}}=\dfrac{ln(2)}{\lambda}

Put the value into the formula

T_{\dfrac{1}{2}}=\dfrac{ln(2)}{1.55\times10^{-5}}

T_{\dfrac{1}{2}}=44.719\times10^{3}\ s

T_{\dfrac{1}{2}}=11.3\ hr

(b). We need to calculate the value of N₀

Using formula of N_{0}

N_{0}=\dfrac{3.70\times10^{6}}{\lambda}

Put the value into the formula

N_{0}=\dfrac{3.70\times10^{6}}{1.55\times10^{-5}}

N_{0}=2.38\times10^{11}\ nuclei

(c). We need to calculate the sample's activity

Using formula of activity

R=R_{0}e^{-\lambda\times t}

Put the value intyo the formula

R=10e^{-(1.55\times10^{-5}\times30\times3600)}

R=1.87\ mCi

Hence, (a). The decay constant is 1.55\times10^{-5}\ s^{-1}

The half life is 11.3 hr.

(b). The value of N₀ is 2.38\times10^{11}\ nuclei

(c). The sample's activity is 1.87 mCi.

4 0
3 years ago
The force on the wire is directed?
USPshnik [31]

Answer: A

Explanation:

5 0
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An initially uncharged air-filled capacitor is connected to a 3.013.01 V charging source. As a result, 9.91×10−59.91×10−5 C of c
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Answer:

23

Explanation:

7 0
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