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lianna [129]
3 years ago
13

Out of a pair of identical springs of force constants, 240Nm-1 one is compressed by 10 cm and the other is stretched by 10 cm. W

hat is the difference in the potential energies stored in the two springs?​
Don't spam ❌
Physics
2 answers:
Nadusha1986 [10]3 years ago
6 0

Explanation:

<h3>Answer is zero</h3>

The stored potential energy of a spring is independent whether it is compressed or expanded

This doesn't depend upon movement in left from natural length or right.

This is because the spring always does negative work and opposite to the direction of motion.

<h3>Mathematically AlsoP=\sf \orange{  \frac{1}{2} kx^2}</h3>

<h3>-XxItzAdiXx</h3>
rosijanka [135]3 years ago
3 0

Answer:

U=1/2kx²

U1=1/2×240×(-10/100)²

U2=1/2×240×(10/100)²

difference, ️U=U1-U2=0

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An empty rubber balloon has a mass of 0.0120 kg. The balloon is filled with helium at 0°C, 1 atm pressure, and a density of 0.17
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Answer:

a) F_b = 6.62 N

b) F_net = 5.583 N

Explanation:

Given:

- Conditions of He gas:  T = 0 C , P = 1 atm , ρ = 0.179 kg/m^3

- The mass of balloon m = 0.012 kg

- The radius of balloon r = 0.5 m

Find:

a)What is the magnitude of the buoyant force acting on the balloon?

b)What is the magnitude of the net force acting on the balloon?

Solution:

- The buoyant force F_b acting on the balloon is equal to the weight of the air it displaces.The mass of the displaced air ρ*V is the volume of the balloon times the density of the. Multiplying that by acceleration due to gravity gives its weight.

                                 F_b = ρ*V*g

                                 F_b = 4*ρ*g*pi*r^3 / 3

                                 F_b = 4*1.29*9.81*pi*.5^3 / 3

                                 F_b = 6.62 N

- The net force will be the difference between the balloon’s weight and the buoyant force. The weight of the balloon is the density of the helium times the volume of the balloon added to the mass of the empty balloon.

                                 F_g = ρ*V*g + m*g

                                 F_g = 4*ρ*g*pi*r^3 / 3 + 0.012*9.81

                                 F_g = 4*0.179*9.81*pi*.5^3 / 3 + 0.012*9.81

                                 F_g = 1.037 N

- The net force is the difference between weight and buoyant force

                                F_net = F_g - F_b

                                F_net = 6.62 - 1.037

                                F_net = 5.583 N

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True or false. Magnetic force fields are straight lines.<br> O False<br> O True
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Answer:

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What graph would best represent acceleration as a function of mass when a constant force is applied?
Alex17521 [72]

The graphs of the acceleration as a function of mass and of the acceleration as a function of force are in attachment.

Explanation:

To answer both parts of the question, we refer to Newton's second law, which states that:

F=ma

where

F is the net force on an object

m is the mass of the object

a is its acceleration

a)

To answer this part, we re-arrange the previous equation as follows:

a=\frac{F}{m}

Therefore, we notice that if a constant force is applied, the acceleration is inversely proportional to the mass of the object:

a \propto \frac{1}{m}

this means that if the mass increases, the acceleration decreases, and if the mass decreases, the acceleration increases.

In a graph of acceleration vs mass, the curve representing this relationship would be a hyperbole. The graph is shown as the first graph in the attached picture.

b)

As before, we re-arrange the previous equation as follows:

a=\frac{F}{m}

Here we notice that if the object has a constant mass, the acceleration is directly proportional to the force applied on the object:

a \propto F

this means that when the force increases, the acceleration increases, and when the force decreases, the acceleration decreases.

In a graph of acceleration vs force, the curve representing this relationship would be a straight line, as shown in the second graph in the attached picture.

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Nookie1986 [14]

Answer:

F = 2.6 \times 10^3 N

Explanation:

Maximum height reached by the ball after being popped by the bat is given as

y = 40 m

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now the change in momentum of the ball is given as

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\Delta P = 0.145(28\hat j + 35 \hat i)

now force is given as rate of change in momentum

F = \frac{\Delta P}{\Delta t}

F = \frac{0.145(28\hat j + 35 \hat i)}{2.5 \times 10^{-3}}

F = (1.62 \hat j + 2.03 \hat i)\times 10^3 N

so magnitude of the force is given as

F = \sqrt{1.62^2 + 2.03^2} \times 10^3 N

F = 2.6 \times 10^3 N

4 0
3 years ago
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