Question

Out of a pair of identical springs of force constants, 240Nm-1 one is compressed by 10 cm and the other is stretched by 10 cm. What is the difference in the potential energies stored in the two springs?​
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Answer 1

Explanation:

Answer is zero

The stored potential energy of a spring is independent whether it is compressed or expanded

This doesn't depend upon movement in left from natural length or right.

This is because the spring always does negative work and opposite to the direction of motion.

Mathematically AlsoP=$\sf \orange{ \frac{1}{2} kx^2}$

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Answer 2

Answer:

U=1/2kx²

U1=1/2×240×(-10/100)²

U2=1/2×240×(10/100)²

difference, ️U=U1-U2=0