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3 years ago

What is the colour of Bromine

Chemistry

2 answers:

nydimaria [60]3 years ago

5 0

Reddish brown colour

mote1985 [20]3 years ago

3 0

Bromine in carbon tetrachloride is brown in colour. It is used to detect unsaturation in an organic compound. The brown colour of the solution is decolourised if unsaturation is present in the compound.

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Chemicals are classified as health hazards when they pose which of the following hazardous effects?

AlexFokin [52]

Answer:

poisoning, breathing problems, skin rashes, allergic reactions, allergic sensitisation, cancer, and other health problems from exposure.

Explanation:

many hazardous chemicals are also classified as dangerous goods.

4 0

2 years ago

What are the 4 different types of chemical reactions? And how to remember them

Tju [1.3M]

<span>Synthesis, decomposition, single replacement and double replacement.</span>

4 0

3 years ago

Read 2 more answers

How many elements and atoms are in marble

DochEvi [55]

Answer:

Explanation:

Scientists know that there are 6x1023 molecules in a mole - so we have about 0.5x1023 molecules in our marble…and since every silicon dioxide molecule has one atom of silicon and two of oxygen, we have a grand total of 1.5x1023 atoms. That's 150,000,000,000,000,000,000,000 atoms

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3 years ago

Given the value of the equilibrium constant (Kc) for the equation (a), calculate the equilibrium constant for equation (b)

matrenka [14]

Answer: The value of equilibrium constant for new reaction is $1.92\times 10^{-25}$

Explanation:

The given chemical equation follows:

$O_2(g)\rightarrow \frac{2}{3}O_3(g)+\frac{1}{2}O_2(g)$

The equilibrium constant for the above equation is $5.77\times 10^{-9}$

We need to calculate the equilibrium constant for the equation of 3 times of the above chemical equation, which is:

$3O_2(g)\rightarrow 2O_3(g)$

The equilibrium constant for this reaction will be the cube of the initial reaction.

If the equation is multiplied by a factor of '3', the equilibrium constant of the new reaction will be the cube of the equilibrium constant of initial reaction.

The value of equilibrium constant for reverse reaction is:

$K_{eq}'=(5.77\times 10^{-9})^3=1.92\times 10^{-25}$

Hence, the value of equilibrium constant for new reaction is $1.92\times 10^{-25}$

5 0

3 years ago

What is the average atomic mass of a sample of naturally occurring x, if it is comprised of the following isotopes 47% ^51X, 17%

iogann1982 [59]

What your going to do is take away the lowest number form the highest and subtract. Thats your answer...

8 0

3 years ago