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3 years ago

12

If 50 milliliters of 0.50 M HCl is used to completely neutralize 25 milliliters of KOH solution, what is the molarity of the bas

e?

1 answer:

NemiM [27]3 years ago

3 0

Answer:

0.25 M

Explanation:

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If a 100. -g sample of a hydrated compound contains 37.07-g sodium, 48.39-g carbonate and 14.54-g water, find the empirical form

Mumz [18]

he required empirical formula based on the data provided is Na2CO3.H2O.

<h3>What is empirical formula?</h3>

The term empirical formula refers to the formula of a compound which shows the ratio of each specie present.

We have the following;

Mass of sodium = 37.07-g

Mass of carbonate = 48.39 g

Mass of water = 14.54-g

Number of moles of sodium = 37.07-g/23 g/mol = 2 moles

Number of moles of carbonate = 48.39 g/61 g/mol = 1 mole

Number of moles of water = 14.54/18 g/mol = 1 mole

The mole ratio is 2 : 1: 1

Hence, the required empirical formula is Na2CO3.H2O

Learn more about empirical formula : brainly.com/question/11588623

3 0

2 years ago

Plz help, have a quiz on this plz PLZ

katovenus [111]

Answer:

20.82

Explanation:

7 0

3 years ago

What is the mass of one mole of nitrogen atoms?

OLEGan [10]

Answer:

28.0

Explanation:

4 0

3 years ago

Read 2 more answers

A 0.0000792 M sample of Compound X in a solvent has an absorbance of 0.341 at 528 nm in a 1.000-cm cuvet. The solvent alone has

natima [27]

Answer:

a) a = 3485 M⁻¹cm⁻¹

b) C = 0,000127 M

Explanation:

Lambert-Beer law says that there is a linear relationship between absorbance and concentration of a chemical substance. The formula is:

A = a×b×C

Where A is absorbance, a is molar absorptivity, b is path length and C is concentration.

a) In the problem Concentration is 0.0000792 M, b is 1,000cm and Absorbance is absorbance of sample-absorbance of blank: 0,341-0,065 = 0,276

Replacing:

0,276 = a×1,000cm×0,0000792M

<em>a = 3485 M⁻¹cm⁻¹</em>

b) As the experiment consist in the same compound in the same solvent, the molar absorptivity will be the same, a = 3485 M⁻¹cm⁻¹, path length will be 1,000cm and absorbance: 0,508-0,065 = 0,443

Replacing:

0,443 = 3485 M⁻¹cm⁻¹×1,000cm×C

<em>C = 0,000127 M </em>

<em></em>

I hope it helps!

8 0

3 years ago

SOLVE The density of a gas is 0.68 g/mL. What amount of space would 23.8 g of this gas occupy?

Contact [7]

Answer:

<h2>The answer is 35 mL</h2>

Explanation:

Density of a substance can be found by using the formula

$Density(\rho) = \frac{mass}{volume}$

From the question we are finding the amount of space the gas will occupy that's the volume of the gas

Making volume the subject we have

$volume = \frac{mass}{Density}$

From the question

mass = 23.8 g/mL

Density = 0.68 g/mL

Substitute the values into the above formula and solve

That's

$volume = \frac{23.8}{0.68}$

We have the final answer as

<h3>35 mL</h3>

Hope this helps you

6 0

3 years ago