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charle [14.2K]
3 years ago
12

If 50 milliliters of 0.50 M HCl is used to completely neutralize 25 milliliters of KOH solution, what is the molarity of the bas

e?
Chemistry
1 answer:
NemiM [27]3 years ago
3 0

Answer:

0.25 M

Explanation:

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Calculate the mass ratio of S to O in SO, and then calculate the mass ratio of S to O in SO2, given that the mass of S is approx
ziro4ka [17]

Explanation:

From the knowledge of law of multiple proportions,

mass ratio of S to O in SO:

mass of S : mass of O

= 32 : 16

= 32/16

= 2/1

mass ratio of S to O in SO2:

= mass of S : 2 × mass of O

= 32 : 2 × 16

= 32/32

= 1/1

ratio of mass ratio of S to O in SO to mass ratio of S to O in SO2:

= 2/1 ÷ 1/1

= 2

Thus, the S to O mass ratio in SO is twice the S to O mass ratio in SO2.

8 0
3 years ago
How many atoms of oxygen are represented in 3Fe(NO3)2?
nexus9112 [7]
There are 18. In each molecule of Fe(NO3)2 there are 6 oxygen atoms because you have 2 nitrate (NO3) components which each contain 3 oxygen atoms. 2 x 3 = 6. Because you have 3 molecules of Fe(NO3)2, you need to multiply 6 by 3, which gives you 18 oxygen atoms.
4 0
3 years ago
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List 3 elements that have similar properties or reactivity. Justify your answer with reasoning.
Rus_ich [418]

Answer:

Lithium, Potassium and Calcium

Explanation:

Because they are all in group one of the periodic table

7 0
3 years ago
No explanation needed, just a quick answer please!
tresset_1 [31]

all of the above is the answer :)

8 0
3 years ago
By pipet, 11.00 mL of a 0.823 MM stock solution of potassium permanganate (KMnO4) was transferred to a 50.00-mL volumetric flask
tangare [24]

Answer:

1) 0.18106 M is the molarity of the resulting solution.

2) 0.823 Molar is the molarity of the solution.

Explanation:

1) Volume of stock solution = V_1=11.00 mL

Concentration of stock solution = M_1=0.823 M

Volume of stock solution after dilution = V_2=50.00 mL

Concentration of stock solution after dilution = M_2=?

M_1V_1=M_2V_2 ( dilution )

M_2=\frac{0.823 M\times 11.00 mL}{50 ,00 mL}=0.18106 M

0.18106 M is the molarity of the resulting solution.

2)

Molarity of the solution is the moles of compound in 1 Liter solutions.

Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}

Mass of potassium permanganate = 13.0 g

Molar mass of potassium permangante = 158 g/mol

Volume of the solution = 100.00 mL = 0.100  L ( 1 mL=0.001 L)

Molarity=\frac{13.0 g}{158 g/mol\times 0.100 L}=0.823 mol/L

0.823 Molar is the molarity of the solution.

6 0
3 years ago
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