Answer:
Lead atoms have 82 electrons and the shell structure is 2.8. 18.32. 18.4.
Explanation:
The ground state electron configuration of ground state gaseous neutral lead is [Xe].
Answer:
<h3>The answer is 2 g/cm³</h3>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 48 g
volume = 24 cm³
We have
We have the final answer as
<h3>2 g/cm³</h3>
Hope this helps you
Answer:
The role that chlorine atoms have in increasing the depeltion rate ozone is that Cl acts as a catalyst.
Explanation:
- From the two steps of the reaction:
- O₃ + Cl· → ClO· + O₂
- ClO· + O → Cl· + O₂
- The overall reaction is: O₃ + O → 2O₂
- It is clear that ClO· is an intermediate that has been produced within the first step and has been consumed in the second step.
- Also, Cl· is considered as a catalyst in this reaction that it has been consumed in the first step and has been produced in the second step, which means that it does not get up in the reaction, that is the main characteristic of the catalyst.
- The catalyst usually increases the rate of the reaction by lowering its energy of activation (The minimum energy that is required to initiate the reaction) by proceeding the reaction in an alternative pathway <em>(changing the reaction mechanism)</em>.
- Hence, the role affecting the reaction rate that chlorine atoms have in increasing the depletion rate of ozone that it acts as a catalyst and does not get used up in the reaction.
Answer:
The hydrogen ion concentration of the substance is 3.16*10⁻⁵ M
Explanation:
pH is a parameter used to measure the degree of acidity or alkalinity of a substance. The pH is calculated as the negative logarithm (base 10) of the concentration of hydronium ions [H₃O⁺] or hydrogen ions [H⁺].
pH= - log [H₃O⁺]= - log [H⁺]
Values on the pH scale range from 0 to 14, where pH equal to 7 is neutral, below 7 is acidic and above 7 is basic.
In this case, pH= 4.5
So:
4.5= - log [H⁺]
Solving:
[ H⁺]= 10⁻⁴ ⁵
[H⁺]= 3.16*10⁻⁵ M
The hydrogen ion concentration of the substance is 3.16*10⁻⁵ M
K₂CrO₄(aq) + Ba(NO₃)₂(aq) = BaCrO₄(s) + 2KNO₃(aq)
2K⁺ + CrO₄²⁻ + Ba²⁺ + 2NO₃⁻ = BaCrO₄ + 2K⁺ + 2NO₃⁻
spectator ions: K⁺, NO₃⁻
