Answer:
Answer E.
For a collision to be completely elastic, there must be NO LOSS in kinetic energy.
We can go through each answer choice:
A. Since the ball rebounds at half the initial speed, there is a loss in kinetic energy. This is NOT an elastic collision.
B. A collision involving sticking is an example of a perfectly INELASTIC collision. This is NOT an elastic collision.
C. A reduced speed indicates that there is a loss of kinetic energy. This is NOT elastic.
D. The balls traveling at half the speed after the collision indicates a loss of kinetic energy, making this collision NOT elastic.
E. This collision indicates an exchange of velocities, characteristic of an elastic collision. We can prove this:
Let:
m = mass of each ball
v = velocity
We have the initial kinetic energy as:
KE = \frac{1}{2}mv^2 + 0 = \frac{1}{2}mv^2KE=21mv2+0=21mv2
And the final as:
KE = 0 + \frac{1}{2}mv^2 = \frac{1}{2}mv^2KE=0+21mv2=21mv2
uranium oxide
Hope This Helps! Have A Nice Day!!
The answer is c because thats the number when combined with a metal. +1 is when its combined with a nonmetal.
<span>air = 70 % N2
exhaled air =70%N2 + some less O2 compared to only air
2H2O2=2H2O+O2
NaHCO3=2NaHCO3 → Na2CO3 + H2O + CO2 = No O2 gas from decomposition
ssoooo NaHCO3 <exhaled air <air <H2O2
SO sorry for the long wait, hope I helped.
</span>
Answer:
Catod: K^(+), H2O
2H2O + 2e^(-) ---> H2 + 2OH^(-) reduction reaction
Anod: I^(-), H2O
2I^(-) ---> I2 + 2e^(-) oxidation reduction
2H2O + 2I^(-) ---> I2 + H2 +2OH^(-) ionic net reaction
