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Mandarinka [93]
3 years ago
6

HELP ASAP PLEASE I WILL MARK BRAINIST

Chemistry
2 answers:
Oduvanchick [21]3 years ago
6 0

Answer: The Answer Is C

Explanation:

jeka57 [31]3 years ago
4 0
It is iodine! I. Last answer.
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What is the osmotic pressure of a 0.850 m solution of glucose in water at 35 °c?
Alik [6]

The osmotic pressure of the glucose solution is 21.49 atm.

From the question given above, the following data were obtained:

  • Molarity (M) = 0.85 M
  • Temperature (T) = 35 °C = 35 + 273 = 308 K
  • Van't Hoff's factor (i) = 1 (non-electrolyte)
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Osmotic pressure (π) =?

π = iMRT

π = 1 × 0.85 × 0.0821 × 308

π = 21.49 atm

Therefore, the osmotic pressure is 21.49 atm

Learn more about osmotic pressure: brainly.com/question/19533851

8 0
2 years ago
In a reaction, 25 grams of reactant
Vsevolod [243]

Answer:

D. 15g

Explanation:

The law of conservation of mass states that, in a chemical reaction, mass can neither be created nor destroyed. This means that the amount of matter in the elements of the reactants must be equal to the amount in the resulting products.

In this question, 25 grams of a reactant AB, was broken down in a reaction to produce 10 grams of products A and X grams of product B. According to the law of conservation of mass, the mass of the reactant must be equal to the total mass of the products. This means that 25 grams must also be the total mass of both products in this reaction. Hence, if product A is 10 grams, product B will be 25 grams - 10 grams = 15 grams.

Therefore, product B must be 15 grams in order to form a total of 25 grams when added to the mass of product A. This will equate the mass of the reactant AB and fulfill the law of conservation of mass.

8 0
3 years ago
The amount of matter in a object is referred as:
mestny [16]
Volume is the thing
…………….
4 0
3 years ago
If I add water to 100ml of a 0.15m potassium sulfate until the final volume is 150ml what will the molarity of the diluted solut
Delicious77 [7]

Answer:

0.1 M is the answer and I have explained it in the attachment below.

Hope this helped!

8 0
3 years ago
Calculate the volume a solution required toof provide the following: (a) 2.14 g of sodium chloridefrom a 0.270 M solution, (b) 4
enyata [817]
A) NaCl = 58.44 g/mol

number of moles :  2.14 / 58.44 = 0.0366 moles

V = n / M  => 0.0366 / 0.270 = 0.1355 L 
__________________________________________

b) C2H6<span>O = 46.06 g/mol

</span>number of moles :  4.30 / 46.06 = 0.0933 moles

<span>V = n / M  => 0.0933 / 1.50 = 0.0622 L 
</span>___________________________________________

c) CH3COOH = 60.0 g/mol

number of moles :  0.85 / 60.0= 0.0141 moles

V = n / M  =>  <span> 0.0141 </span>/ 0.30 = 0.047 L 
___________________________________________

hope this helps!
3 0
3 years ago
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