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3 years ago

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What compotent of air is least nessasery for life on earth

1 answer:

taurus [48]3 years ago

5 0

Answer:

Oxygen is the component of air necessary for life on Earth. All living organisms require it for respiration.

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What happens to glucose in the Calvin cycle? <br><br> Plz help

Leona [35]

The reactions of the Calvin cycle add carbon from carbon dioxide in the atmosphere to a five-carbon molecule known as RuBP. These reactions use chemical energy that were produced in the light reactions, from NADPH and ATP. The final product of the Calvin cycle is glucose.

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3 years ago

ASAP pleaseee and Thankyou

Afina-wow [57]

All of the boxes in the chart are Gg

1. 100%

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2 years ago

Ascorbic acid, of vitamin c (c6h8o6), is an essential vitamin. it cannot be stored by the body and must be present in the diet.

Inessa [10]

Molecular formula of ascorbic acid is $C_{6}H_{8}O_{6}$

Molar mass of ascorbic acid = $(6 * 12 g/mol) + (8 * 1 g/mol) + (6 * 16 g/mol) = 176 g/mol$

Converting 500.0 mg of ascorbic acid to moles: We use molar mass of ascorbic acid to convert mass to moles.

$500.0 mg * \frac{1 g}{1000 g} *\frac{1 mol}{176 g} = 0.00284 mol$

Converting 500.0 mg of ascorbic acid to molecules: The conversion factor used is 1 mole = $6.022*10^{23} molecules$

$500.0 mg * \frac{1 g}{1000 mg}*\frac{1 mol}{176 g} * \frac{6.022*10^{23}molecules}{1 mol} = 1.71 * 10^{21} molecules$

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3 years ago

Read 2 more answers

For the first order process: AB The half-life of A is 62.1 seconds. If a sample of A initially has 250.0 g, what mass (in g) of

Molodets [167]

<u>Answer:</u> The mass of sample A after given time is 99.05 g.

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

We are given:

$t_{1/2}=62.1s$

Putting values in above equation, we get:

$k=\frac{0.693}{62.1}=0.011s^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.011s^{-1}$

t = time taken for decay process = 84.2 s

$[A_o]$ = initial amount of the reactant = 250 g

[A] = amount left after decay process = ?

Putting values in above equation, we get:

$0.011s^{-1}=\frac{2.303}{84.2s}\log\frac{250}{[A]}$

$[A]=99.05g$

Hence, the mass of sample A after given time is 99.05 g.

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2 years ago

There are several different models that represent compounds. One type of model is shown.

d1i1m1o1n [39]

A) structural formula

On edge

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2 years ago

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