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belka [17]
3 years ago
8

A king has no sons, no daughters, and no queen. For this reason he must decide who will take the throne after he dies. To do thi

s he decides that he will give all of the children of the kingdom a single seed. Whichever child has the largest, most beautiful plant will earn the throne; this being a metaphor for the kingdom.At the end of the contest all of the children came to the palace with their enormous and beautiful plants in hand. After he looks at all of the children's pots, he finally decides that the little girl with an empty pot will be the next Queen. Why did he choose this little girl over all of the other children with their beautiful plants?
Physics
2 answers:
ZanzabumX [31]3 years ago
3 0
The king gave them all fake seeds,  the little girl was the only honest child who didn't switch seeds.
AveGali [126]3 years ago
3 0
The king gave them all fake seeds and the little girl was the only one who didn't switch seeds.

Hope that helps.
You might be interested in
Why is it important for DNA to be copied before cell division?
KATRIN_1 [288]
If DNA is improperly copied, the cell will function differently.
This is called a mutation.
Mutated cells do not do the originally intended purpose.
4 0
3 years ago
1) Little Timmy wants to measure how tall his house is. He doesn’t have a tape measure but does have a stopwatch. He recruits Bi
kifflom [539]

1) 13.7 m

The motion of the rock is a free fall, with constant acceleration g=9.8 m/s^2 towards the ground, so the total distance it covers is given by the SUVAT equation:

S=\frac{1}{2}gt^2

where S is the height of the house, and t is the time the rock takes to reach the ground. Substituting t=1.67 s, we find:

S=\frac{1}{2}(9.8 m/s^2)(1.67 s)^2=13.7 m

2) 105.5 m

The motion of the stuffed chicken is a projectile motion, with a uniform horizontal motion (with constant velocity of v=36.0 m/s) and a vertical accelerated motion (with constant acceleration of g=9.8 m/s^2).

First of all, we can find the total time of the ball by considering the vertical motion only. We know the vertical distance covered, S=42.2 m, so the time of the fall is

S=\frac{1}{2}gt^2\\t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2(42.2 m)}{9.8 m/s^2}}=2.93 s

And now we can consider the horizontal motion to find the horizontal distance covered by the stuffed chicken:

d=vt=(36.0 m/s)(2.93 s)=105.5 m

3) 49.4 m

Again, the motion of the ball is a projectile motion, with a horizontal motion and a vertical motion.

The range of a projectile launched from the ground can be found by using the formula:

d=\frac{v^2}{g} sin 2 \theta

where, in this case:

v = 22.0 m/s is the initial velocity

\theta=45^{\circ}

Substituting into the formula, we find

d=\frac{(22.0 m/s)^2}{9.8 m/s^2}(sin (2\cdot 45^{\circ}))=49.4 m

4) 9.6 m/s^2

The frictional force acting on the monkey is given by:

F_f = \mu mg=(0.16)(31.0 kg)(9.8 m/s^2)=48.6 N

where \mu is the coefficient of friction and m is the mass of the monkey.

We have two forces acting on the monkey: the push of F=345 N and the frictional force acting in the opposite direction. According to Newton's second law, the net force will be equal to the product between the monkey's mass and its acceleration, so we can find the acceleration:

F-F_f=ma\\a=\frac{F-F_f}{m}=\frac{345 N-48.6 N}{31.0 kg}=9.6 m/s^2

5) 462.3 N

The horizontal component of the pushing force is:

F_x = F cos \theta = (648 N)(cos 25^{\circ})=587.3 N

The frictional force, acting in the opposite direction, is

F_f = \mu mg=(0.17)(75.0 kg)(9.8 m/s^2)=125.0 N

where \mu is the coefficient of friction and m is the mass of the box.

The net force on the box is therefore given by the net force on the horizontal direction:

F_{net}=F_x -F_f=587.3 N -125.0 N=462.3 N

6) 89.5 N

First of all we need to calculate the total weight of the table and the items above it.

The weight of the table is:

W=mg=(25.0 kg)(9.8 m/s^2)=245 N

So the total weight of the table and the items is

W=245 N+63 N+12 N+44 N+24 N+9N+10N=407 N

The force needed to get the table moving must be at least equal to the frictional force, which is equal to the product between the coefficient of friction and the weight of the all stuff:

F=F_f = \mu W=(0.22)(407 N)=89.5 N

7 0
2 years ago
Which of the following statements about the
Komok [63]

Answer: the answer is A

Explanation: just did it

8 0
3 years ago
An arrow of mass 20 g is shot horizontally into a bale of hay, striking the hay with a velocity of 60 m/s. It penetrates a depth
goblinko [34]

From the question, The kinetic energy of the fired arrow is equal to the work done by the bale of hale in stopping the arrow.

We make use of the following formula

mv²/2 = F'd................... Equation 1

Where

  • m = mass of the arrow
  • v = velocity of the arrow
  • F' = average stopping force acting on the arrow
  • d = distance of penetration

Make F' the subject of the equation

F' = mv²/2d.................. Equation 2

From the question,

Given:

  • m = 20 g = 0.02 kg
  • v = 60 m/s
  • d = 40 cm = 0.4 m

Substitute these values into equation 2

  • F' = 0.02(60²)/(0.4×2)
  • F' = 72/0.8
  • F' = 90 N

Hence, The average stopping force acting on the arrow is 90 N

Learn more about average stooping force here: brainly.com/question/13370981

5 0
2 years ago
A person 1.8m tall stands 0.75m from a reflecting globe in a garden.
Maru [420]

Answer:

1. The image of the person is 1.41 m, virtual and formed at the back of the surface of the globe.

2. The person's image is 3.38 m tall.

Explanation:

From the given question, object distance, u = 0.75 m, object height = 1.8 m, radius of curvature of the reflecting globe, r = 8 cm = 0.08 m.

f = \frac{r}{2} = \frac{0.08}{2} = 0.04 m

1. The image distance, v, can be determined by applying mirror formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

\frac{1}{0.04} = \frac{1}{0.75} + \frac{1}{v}

\frac{4}{100} - \frac{75}{100} = \frac{1}{v}

\frac{1}{v} = \frac{4 - 75}{100}

  = - \frac{71}{100}

⇒ v = -\frac{100}{71}

      = - 1.41 m

The image of the person is 1.41 m, virtual and formed at the back of the surface of the globe.

2.  \frac{image distance}{object distance} = \frac{image height}{object height}

  \frac{1.41}{0.75} = \frac{v}{1.8}

v = \frac{2.538}{0.75}

  = 3.384

v = 3.38 m

The person's image is 3.38 m tall.

6 0
3 years ago
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