Answer:
They are the physical parts of a computer.
examples :monitor,keyboard,system unit and mouse.
The answer is a. 0.14 kg
PE = mgh
116.62 = m•(9.8)•(85)
m = 116.62/(9.8•85)
= 0.14 kg
Answer:
The torque in the coil is 4.9 × 10⁻⁵ N.m
Explanation:
T = NIABsinθ
Where;
T is the torque on the coil
N is the number of loops = 9
I is the current = 7.8 A
A is the area of the circular coil = ?
B is the Earth's magnetic field = 5.5 × 10⁻⁵ T
θ is the angle of inclination = 90 - 56 = 34°
Area of the circular coil is calculated as follows;
T = 9 × 7.8 × 0.0227 × 5.5×10⁻⁵ × sin34°
T = 4.9 × 10⁻⁵ N.m
Therefore, the torque in the coil is 4.9 × 10⁻⁵ N.m
Answer:
a) t = 0.528 s
b) D = 1.62 m
Explanation:
given,
speed of the baseball = 3.75 m/s
angle made with the horizontal = 35°
height of the roof edge = 2.5 m
using equation of motion
4.9 t² + 2.15 t - 2.5 = 0
on solving the above equation
t = 0.528 s
b) D = v cos θ × t
D = 3.75 × cos 35° ×0.528
D = 1.62 m
Answer:
A) 19.994 m B) 1.750 seconds
Explanation:
We are asked about time and height at which both balls pass at the same height. So both, <em>TIME </em>and <em>HEIGHT</em> of both vertical trajectories are the same.
To find the values we use the kinematics expression for vertical motion with constant acceleration, using as the gravity acceleration -9.8 m/s2. Motion downwards is negative and upwards is positive. The reference point is the bottom of the building. The equation is as follow:
For each ball this equation is:
Since the data of the problem is using SI units, then our answers will be expressed in SI units as well. Now, we first compute part B by equaling both equations (same height) and solving for time:
With this time we can find the Height by substituting it in any equation of the balls. In this case, we use the expression of ball B