Answer:
hello your question lacks some data and required diagram
G = 77 GPa, т all = 80 MPa
answer : required diameter = 252.65 * 10-^3 m
Explanation:
Given data :
force ( P ) = 660 -N force
displacement = 15 mm
G = 77 GPa
т all = 80 MPa
i) Determine the required diameter of shaft BC
considering the vertical displacement ( looking at handle DC from free body diagram )
D' = 0.3 sin∅ , where D = 0.015
hence ∅ = 2.8659°
calculate the torque acting at angle ∅ of CD on the shaft BC
Torque = 660 * 0.3 cos∅
= 660 * 0.3 * cos 2.8659 = 198 * -0.9622 = 190.5156 N
hello attached is the remaining part of the solution
Answer:
<h2> Ah Filipino ka rin?</h2>
Explanation:
<h2>Saya nmen</h2>
Answer:
8.6 miles
Explanation:
In order to calculate the straight-line distance between the starting point and the ending point, we need to resolve each part of the displacement into two perpendicular directions, let's say horizontal (x) and vertical (y) directions.
In the first part, Erica moves for 5.2 miles 25∘ north of east. Resolving into the two directions:
In the second part, Erica moves 5.0 miles north, so the components are
So the components of the net displacement are
And the magnitude of the net displacement is
Answer:296.76 N
Explanation:
Given
mass of box 
Let 
be the Tension in left side and 
be the Tension in the right side
From diagram
and
![T_2\left [ \tan 80\cdot \cos 65+\sin 65\right ]=100\cdot g](https://tex.z-dn.net/?f=T_2%5Cleft%20%5B%20%5Ctan%2080%5Ccdot%20%5Ccos%2065%2B%5Csin%2065%5Cright%20%5D%3D100%5Ccdot%20g)
![T_2=\frac{100\cdot g}{\left [ \tan 80\cdot \cos 65+\sin 65\right ]}](https://tex.z-dn.net/?f=T_2%3D%5Cfrac%7B100%5Ccdot%20g%7D%7B%5Cleft%20%5B%20%5Ctan%2080%5Ccdot%20%5Ccos%2065%2B%5Csin%2065%5Cright%20%5D%7D)
