What travels on a wave

A.) If its booster rockets accelerate the space shuttle at 15m/s2, how high will it be one minute after launch?

poizon [28]

Answer:

27,000 m

450 m/s

Explanation:

Assuming the initial velocity is 0 m/s:

v₀ = 0 m/s

a = 15 m/s²

t = 60 s

A) Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (60 s) + ½ (15 m/s²) (60 s)²

Δy = 27,000 m

B) Find: v_avg

v_avg = Δy / t

v_avg = 27,000 m / 60 s

v_avg = 450 m/s

5 0

2 years ago

How fast does a 2 MeV fission neutron travel through a reactor core?

Artemon [7]

Answer:

The answer is $1.956 \times 10^7\ m/s$

Explanation:

The amount of energy is not enough to apply the relativistic formula of energy $E = mc^2$ , so the definition of energy in this case is

$E = \frac{1}{2}m v^2$ .

From the last equation,

$v= \sqrt{2E/m}$

where

$E = 2 MeV = 3.204 \times 10^{-13} J$

and the mass of the neutron is

$m = 1.675\times 10^{-27}\ Kg$ .

Then

$v = 1.956 \times 10^7\ m/s$

the equivalent of $0.065$ the speed of light.

5 0

2 years ago

1. You place an object 63 cm in front of a converging lens, with a 40 cm focal length.

NikAS [45]

Answer:

1.

109.6 cm , - 1.74 , real

2.

1.5

Explanation:

1.

d₀ = object distance = 63 cm

f = focal length of the lens = 40 cm

d = image distance = ?

using the lens equation

$\frac{1}{f} = \frac{1}{d_{o}} + \frac{1}{d}$

$\frac{1}{40} = \frac{1}{63} + \frac{1}{d}$

d = 109.6 cm

magnification is given as

$m = \frac{-d}{d_{o}}$

$m = \frac{-109.6}{63}$

m = - 1.74

The image is real

2

d₀ = object distance = a

d = image distance = - (a + 5)

f = focal length of lens = 30 cm

using the lens equation

$\frac{1}{f} = \frac{1}{d_{o}} + \frac{1}{d}$

$\frac{1}{30} = \frac{1}{a} + \frac{1}{- (a + 5)}$

a = 10

magnification is given as

$m = \frac{-d}{d_{o}}$

$m = \frac{- (- (a +5))}{a}$

$m = \frac{(5 + 10)}{10}$

m = 1.5

6 0

2 years ago

If the absolute pressure of a gas is 550.280 kPa, its gage pressure is A. 101.325 kPa. B. 651.605 kPa. C. 448.955 kPa. D. 277.28

guajiro [1.7K]

Answer:

Option C is the correct answer.

Explanation:

Absolute pressure is sum of gauge pressure and atmospheric pressure.

That is

$P_{abs}=P_{gauge}+P_{atm}$

We have

$P_{abs}=550.280 kPa\\\\P_{atm}=1atm=101325Pa=101.325kPa$

Substituting

$P_{abs}=P_{gauge}+P_{atm}\\\\550.280=P_{gauge}+101.325\\\\P_{gauge}=448.955kPa$

Option C is the correct answer.

7 0

2 years ago

a person throws a ball in such a way that its speed is zero at one particular point in its path. How did the person throw the ba

Keith_Richards [23]

vertical! or in other words, up!

6 0

3 years ago