The mass percent of iron in the ore is 31.6%
<h3>Steps</h3>
8H⁺(aq) + 5Fe²⁺(aq) + MnO⁻₄(aq) → 5Fe³⁺(aq) + Mn²⁺(aq) + 4H₂O(l)
V(MnO4^-)=39,32 mL
c(MnO4^-)=0,0319M
n(MnO4^-)=c*V=1,254308 mmol
n(Fe^{2+})=5*n(MnO4^-)=6,27 mmol
Equation
Fe+2H->Fe^+2 + H2
n(Fe)=n(Fe^{2+} )=6,27 mmol
m(Fe)=n*Ar=350,27mg=0,35027g
mass percent(Fe in ore)=m(Fe)/m(ore)*100
=31,61 percent
The mass percent of iron in the ore is 31.6%
<h3>What is the equation for the balance formula?</h3>
An equation for a chemical reaction is said to be balanced if both the reactants and the products have the same number of atoms and total charge for each component of the reaction. In other words, both sides of the reaction have an equal balance of mass and charge.
<h3>An illustration of a balanced equation</h3>
For instance, consider about the reaction: O2 (g) + 2Mg(s) = 2MgO (g) Two magnesium and two oxygen atoms are present in this reaction on both the reactant and product sides.
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