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3 years ago

Why do scientists use models to study atoms?

1 answer:

3 0

Because atoms are the small and can't be seen by your eyes. It is so small that scientists need to use a model. A model help scientists study things. So, scientists needs to study atoms using models.

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What happens when an object heats up? what happens when an object cools down?

Nataly_w [17]

Answer:

Heat will flow from the hotter object to the colder. The molecules in the hotter object will slow down and the molecules in the colder object will speed up. Eventually they will get to the point where they have the same temperature. This happens all the time around you.

Explanation:

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3 years ago

Read 2 more answers

All of the following affect toxicity of a substance except*

Studentka2010 [4]

Answer:

durage

Explanation:

durage just doesn't make sense compared to the other 3

8 0

3 years ago

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Two reasons why scientists create models to study atoms

zaharov [31]

Models are used to study atoms because we can't exactly study an atom with the naked eye, Using an enlarged model of an atom easier to study because we can pin point the different characteristics of the atom.

6 0

3 years ago

How many atoms of carbon are present in 1.0 g of c6h12o6?

REY [17]

I don't know Im just Trying to get points somehow

4 0

4 years ago

DUE TODAY EXTREMELY IMPORTANT PLEASE PLEASE PLEASE HELP ME ASAPPPPPPPP CHEMISTRY!!!!!!!!!!!!!!!!!!! I WOULD APPRECIATE IT ALOT T

musickatia [10]

Answer:

Here's what I get

Explanation:

3. Molar concentration by formula.

$\begin{array}{rcl}M_{\text{a}}V_{a} & = & M_{\text{b}}V_{b}\\M_{a} \times \text{0.025 00 L} & = & \text{0.3840 mol/L} \times \text{0.034 52 L}\\0.025 00M_{a}\text{ L} & = & \text{0.013 26 mol}\\M_{a}&= &\dfrac{\text{0.013 26 mol}}{\text{0.025 00 L}}\\\\& = &\textbf{0.5302 mol/L}\end{array}$

(i) Comparison of molar concentrations

The formula gives a calculated value of 0.5302 mol·L⁻¹.

Dimensional analysis gives a calculated value of 0.1767 mol·L⁻¹.

The first value is three times the second.

It is wrong because the formula assumes that the acid supplies just enough moles of H⁺ to neutralize the OH⁻ from the NaOH.

Instead, I mol of H₃PO₄ provides 3 mol of H⁺, so your calculated concentration is three times the true value.

(ii) When is the formula acceptable?

The formula is acceptable only when the molar ratio of acid to base is 1:1.

Examples are

HCl + NaOH ⟶ NaCl + H₂O

H₂SO₄ + Ca(OH)₂ ⟶ CaSO₄ + 2H₂O

H₃PO₄ + Al(OH)₃ ⟶ AlPO₄ + 3H₂O

8 0

3 years ago