5. Elements are different because they contain different numbers of protons.

Chemistry

1 answer:

erik [133]2 years ago

4 0

Answer:

True

Explanation:

The number of electrons are what determine an atom.

The number of electrons = number of protons

so the elements are different.

If the number of neutrons are different but the number of electrons and protons are same they are of the same element.

But here the number of protons are different so this is another element.

You might be interested in

What do you think explains why the larger elements are able to form in a supernova explosion? Use evidence from the Supernova 10

lubasha [3.4K]

Larger elements are able to form in a supernova explosion because the star releases very large amounts of energy as well as neutrons, which allows elements heavier than iron to be produced.

<h3>What is Supernova?</h3>

This is referred to the explosion of a star and it resulting in larger elements being formed through a process known as nucleosynthesis and is usually accompanied by an increase in the brightness of the star.

The elements produced are usually larger than elements such as iron and examples include uranium, gold etc.

This is therefore the reason why it was chosen as the most appropriate choice.

Read more about Supernova here brainly.com/question/27492871

#SPJ1

3 0

1 year ago

Need help please :'((((((((((

kati45 [8]

Answer:

you work out the moles by finding the grand formula mass them you divide the actual mass by the grand formula mass: 25/160 (my grand formula mass is probably slightly different from yours) which I got 0.15625 then I times it by 32(O2) and I got 5. but my periodic table is different. it's whole numbers. ;-)

Explanation:

4.44

6 0

2 years ago

Pls help me with this

Zina [86]

Answer:

$[I_2]=[Br]=0.31M$

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to set up the following chemical equation at equilibrium:

$I_2+Br_2\rightleftharpoons 2IBr$

Now, we can set up the equilibrium expression in terms of x (reaction extent) whereas the initial concentration of both iodine and bromine is 0.5mol/0.250L=2.0M:

$K=\frac{[IBr]^2}{[I_2][Br_2]} \\\\1.2x10^2=\frac{(2x)^2}{(2.0-x)^2}$