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3 years ago

How long will your trip take if you travel 4000 m at an average speed of 8m/s

Physics

2 answers:

SpyIntel [72]3 years ago

8 0

Answer:

500 sec

8 min 20 sec

Explanation:

Hi there !

8 m ................ 1 s

4000 m ........ x s

x = 4000m×1s/8m = 500 sec = 8 min 20 sec

Good luck !

Andrews [41]3 years ago

8 0

Answer:8.3mins

Explanation:

S=Vt

where V=average speed

S=4000m V=8m/s

4000=8×t

t=4000/8

t=500s

t=500/60

t=8.3min

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Taking upward motion as positive and downward motion as negative.

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Using equation of motion, we have:

$v_d^2=u^2+2aS\\\\v=\pm\sqrt{u^2+2aS}\\\\v_d=\pm\sqrt{0+2\times -9.8\times -1.25}\\\\v_d=\pm\sqrt{24.5}=\pm4.95\ m/s$

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Given:

Displacement of ball (S) = 0.665 m

Initial velocity ( $v_d$ ) = 4.95 m/s(Upward direction)

Acceleration is due to gravity (g) = -9.8 m/s²

Using equation of motion, we have:

$v_{up}^2=v_d^2+2aS\\\\v_{up}=\pm\sqrt{v_d^2+2aS}\\\\v_{up}=\pm\sqrt{24.5+2\times -9.8\times 0.665}\\\\v_{up}=\pm\sqrt{10.966}=\pm3.31\ m/s$

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$v_{up}=3.31\ m/s$

Now, impulse is equal to change in momentum. So,

Impulse = Final momentum - Initial momentum

$J=m(v_{up}-v_d)\\\\J=(0.150\ kg)(3.31-(-4.95))\ m/s\\\\J=0.150\ kg\times 8.26\ m/s\\\\J=1.239\ Ns$

Therefore, the impulse given to the ball by the floor is 1.239 kg.m/s in upward direction.

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