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Musya8 [376]
1 year ago
11

If an equivalent (eq) is defined as a mole of charge, what is the concentration of ca2 in blood plasma in eq if its concentratio

n is 0.0040 m?
Physics
1 answer:
Andrei [34K]1 year ago
7 0

The concentration of ca2 in blood plasma is comparable if it is 0.0080, according to the supplied statement.

<h3>How do you quantify concentration?</h3>

Subtract the solute's mass from the total volume of the mixture. Calculate C = m/V, where m is the solute's mass and V seems to be the total volume of such solution. Divide the figures you found for mass and volume to find approximate concentration for your solution.

<h3>What is the definition of concentration in the solution?</h3>

A solution's concentration is a measure of how much solute has been dissolved in a specific amount of the solvent or solution. A concentrated solution contains a significant amount or dissolved solute. A dilute solution is one with a little amount of dissolved solute.

<h3>According to the given data:</h3>

The equivalent weight of detail is the mass that combines with someone or displaces 1.008 grams of molecular hydrogen, or eight.

35.5 grams of chlorine or 0 grams of oxygen.

Those figures are the atomic weight divided by that of the normal valence, which is sixteen in the case of oxygen.

One Ca2+ ion has a charge of +2.Calcium ion concentration:

= 0.0040M ⇒ Ca ​​​​2+ Concentration in blood plasma

= 0.0040 × 2⇒ 0.0080 equivalent Ca2

To know more about concentration visit: brainly.com/question/10725862

#SPJ4

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A solid circular shaft and a tubular shaft, both with the same outer radius of c=co = 0.550 in , are being considered for a part
Norma-Jean [14]

Answer:

The power for circular shaft is 7.315 hp and tubular shaft is 6.667 hp

Explanation:

<u>Polar moment of Inertia</u>

(I_p)s = \frac{\pi(0.55)4}2

      = 0.14374 in 4

<u>Maximum sustainable torque on the solid circular shaft</u>

T_{max} = T_{allow} \frac{I_p}{r}

         =(14 \times 10^3) \times (\frac{0.14374}{0.55})

         = 3658.836 lb.in

         = \frac{3658.836}{12} lb.ft

        = 304.9 lb.ft

<u>Maximum sustainable torque on the tubular shaft</u>

T_{max} = T_{allow}( \frac{Ip}{r})

          = (14 \times10^3) \times ( \frac{0.13101}{0.55})

          = 3334.8 lb.in

          = (\frac{3334.8}{12} ) lb.ft

          = 277.9 lb.ft

<u>Maximum sustainable power in the solid circular shaft</u>

P_{max} = 2 \pi f_T

          = 2\pi(2.1) \times 304.9

          = 4023.061 lb. ft/s

          = (\frac{4023.061}{550}) hp

          = 7.315 hp

<u>Maximum sustainable power in the tubular shaft</u>

P _{max,t} = 2\pi f_T

            = 2\pi(2.1) \times 277.9

            = 3666.804 lb.ft /s

            = (\frac{3666.804}{550})hp

            = 6.667 hp

7 0
3 years ago
When is the pressure of the man on the ground more – lying position or standing
Wittaler [7]

Hi,

<u>The man on the ground in standing position has more pressure</u>. This is because when he stands, only his legs are in contact with the ground. While lying, his body is more in contact with the ground, therefore, he exerts less pressure.

To the point, a man standing position on the ground had more pressure.

More is the area of contact, less is the pressure efforted.

Thank you...

7 0
3 years ago
You push a table 8 meters for 16 minuutes and do 6720 j of work how much power do ypu use
Yuri [45]
P=W/t

P=Power
W=Work
t=Time

Convert 16 minutes in seconds:
16 mins = 960 secs

P=6720/960=7.23 W [Watt]
3 0
3 years ago
A cart travels down a ramp at an average speed of 5.00 centimeters/second. What is the speed of the cart in miles/hour? (Remembe
viva [34]
Set up the problem with the conversion rates as fractions where when you multiply the units cancel out leaving the desired units behind.

( \frac{ 5 cm}{1 sec} ) *( \frac{1m }{100cm})*( \frac{1km}{1000m} )*( \frac{1mi}{1.6km} ) = 0.00003125 mi/sec \\  \\ ( \frac{0.00003125 mi}{1sec} )*( \frac{60sec}{1min} )*( \frac{60min}{1hr} )=0.1125 mi/hr
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3 years ago
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If you move 50 meters in 10 seconds, what is your speed ​
iogann1982 [59]

Explanation:

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