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sp2606 [1]
3 years ago
10

Gold has a density of 19300 kg/m³. Calculate the mass of 0.02 m³ of gold in kilograms.

Physics
2 answers:
hjlf3 years ago
7 0

Answer:

Mass = 386 kg

Explanation:

<u><em>Density = Mass / Volume</em></u>

Mass = Density × Volume

Where D = 19300 kg/m³ , V = 0.02 m³

<em>Putting the given in the above formula</em>

Mass = 19300 × 0.02

Mass = 386 kg

Elanso [62]3 years ago
5 0

Answer:

386 kg

Explanation:

mass = density * volume

= 19300 * 0.02

= 386 kg

Hope this helps!

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A ball bearing of radius of 1.5 mm made of iron of density
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\boxed{\sf Viscosity \ of \ glycerine \ (\eta) = 14.382 \ poise}

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\boxed{ \bold{v =  \frac{2}{9}  \frac{( {r}^{2} ( \rho -  \sigma)g)}{ \eta} }}

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\sf \implies \eta =  \frac{2}{9}  \frac{( {(0.15)}^{2}  \times  (7.85 - 1.25) \times 980.6)}{2.25}

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