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3 years ago

X/2-8=19 what is the answer for this equation

Mathematics

2 answers:

ohaa [14]3 years ago

7 0

Answer: 23

Step-by-step explanation:

X/2 - 8 = 19

Tewrite the equation as x/2 - 8/1 =19

=x - 4= 19

Add 4 to both sides of the equation

x = 19 + 4

x = 23

Ilya [14]3 years ago

3 0

Answer:

x=38wh + 16

Step-by-step explanation:

multiply both sides of the equation by 2

move the constant to the right

find the final solution

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Describe how you would find the area of the figure shown at the right.

nikklg [1K]

I would find the area of the shape as if it were a rectangle (5x9) and then subtract the area of two triangles (1/2x2x2.5)

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3 years ago

Read 2 more answers

What is the sum of all the positive integers from √ 24 to √ 102 ?

Eva8 [605]

Answer:

The sum of all positive integers is

5 + 6 + 7 + 8 + 9 + 10

= 45

Step-by-step explanation:

Because $\sqrt{24} = 4.89$ and $\sqrt{102} = 10.09$

So positive numbers between 4.9 and 10.09 are

5+6+7+8+9+10 = 45

Brainliest will be appreciated.

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3 years ago

The approximate height, h, in meters, traveled by golf balls hit with two different clubs over a horizontal distance of d meters

inna [77]

Answer:

a) 100 metres

b) 10 metres

Step-by-step explanation:

Given: the approximate height, h, in meters, travelled by golf balls hit with two different clubs over a horizontal distance of d meters is given by the functions: $h=-0.002d^2+0.3d\,,\,h=-0.004d^2+0.5d$

To find: distances when the ball is at the same height when either of the clubs are used. Also, to find this height

Solution:

(a)

$-0.002d^2+0.3d=-0.004d^2+0.5d\\d(-0.002d+0.3)=d(-0.004d+0.5)\\-0.002d+0.004d=0.5-0.3\\0.002d=0.2\\d=\frac{0.2}{0.002}=100\,\,metres$

(b)

Put d = 100 in $h=-0.002d^2+0.3d$

$h=-0.002(100)^2+0.3(100)\\=-20+30\\=10\,\,metres$

4 0

3 years ago

At which values of x does the function F(x) have a vertical asymptote? Check all that apply. F(x)=2/3x(x-1)(x 5).

Alekssandra [29.7K]

The function F(x) have a vertical asymptote at x =0 and x =1.

Given that

The given Function;

$\rm F(x)=\dfrac{2}{3x(x-1)(x^ 5)}$

We have to determine

At which value the function F(x) has a vertical asymptote.

According to the question

The given Function;

$\rm F(x)=\dfrac{2}{3x(x-1)(x^ 5)}$

The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:

Then,

$\rm 3x (x-1) (x^5)= 0$

$\rm x^5 =0, \ \ x=0\\\\ x-1 = 0, \ \ x =1\\$

The value of x is 0 and 1.

Hence, the function F(x) have a vertical asymptote at x =0 and x =1.

To know more about Parabola click the link given below.

brainly.com/question/12868913

7 0

2 years ago

What x values would be good to use so she does not get fractions for her y values when making the table of ordered pairs.

Ber [7]

Answer:

-3, 0, 3

Step-by-step explanation:

Given, $y = -\frac{4}{3}x + 2$ , the set of x values that will make Kayda not to get y values that are not fraction are -3, 0, 3.

This is so, because,

when x = -3, $y = -\frac{4}{3}(-3) + 2 = \frac{12}{3} + 2 = 4 + 2 = 6$

when x = 0, $y = -\frac{4}{3}(0) + 2 = -0 + 2 = 2$

when x = 3, $y = -\frac{4}{3}(3) + 2 = \frac{-12}{3} + 2 = -4 + 2 = -2$

The correct response is -3, 0, 3

5 0

3 years ago