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Rufina [12.5K]
3 years ago
5

A base of a triangle measures 32 centimeters . what is the measure of the corresponding midsegment of a triangle.

Mathematics
2 answers:
raketka [301]3 years ago
4 0
B.16CM

I hope it helped

soldier1979 [14.2K]3 years ago
3 0
The Midsegment Theorem states that the midsegment of a triangle is half the length of its base. Based on this, the midsegment of a triangle with a base of 32 cm would be B. 16 cm.

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If f(x)=-x^2+6x-1 and g(x) =3x^2-4x-1, find (f-g)(x)
asambeis [7]

Answer:


Step-by-step explanation:

Given,

f(x)=-x^{2} +6x-1\\g(x)=3x^{2} -4x-1

we know,

(f-g)(x)=f(x)-g(x)

So, here we get

(f-g)(x)

=f(x)-g(x)

=-x^{2} +6x-1-(3x^{2} -4x-1)

=-x^{2} +6x-1-3x^{2} +4x+1

=-x^{2}-3x^{2} +6x+4x-1+1

=-4x^{2} +10x

So, the answer is

-4x^{2} +10x

8 0
3 years ago
Read 2 more answers
Factor the expression.
tiny-mole [99]
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The second way is to FOIL them out.  When you check B you get k^{2} -5kf+10kf- 50f^{2} combine your like terms and you have your original expression of k^{2} +5kf-50 f^{2}

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3 0
3 years ago
Find the distance between the points (3,0) and (-1,-5)
nadya68 [22]

Answer:

6.4

Step-by-step explanation:

distance formula \sqrt{(x2-x1)^2+(y2-y1)^2}

\sqrt{(-1-3)^2+(-5-0)^2}

\sqrt{(-4)^2+(-5)^2}

\sqrt{16+25}

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7 0
3 years ago
Pls help me to do the 1st question
serious [3.7K]

Answer:

a) both have same distance

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Step-by-step explanation:

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4 0
3 years ago
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mestny [16]

Answer:

42

Step-by-step explanation:

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h = 42

4 0
3 years ago
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