Answer:
y-3= -6/13 ⋅ (x-6)
Step-by-step explanation:
I hope this helps
The answer is B. hope that help
Answer:
Step-by-step explanation:
Given that X and Y are independent random variables with the following distributions:
x -1 10 1 2 Total
p 0.3 0.1 0.5 0.1 1
xp -0.3 1 0.5 0.2 1.4
x^2p 0.3 10 0.5 0.4 11.2
Mean of X = 1.4
Var(x) = 11.2-1.4^2 = 9.24
y 2 3 5
p 0.6 0.3 0.1 1
yp 1.2 0.9 0.5 0 2.6
y^2p 2.4 2.7 2.5 0 7.6
Mean of Y = 2.6
Var(Y) = 11.2-1.4^2 = 0.84
3) W=3+2x
Mean of w =3+2*Mean of x = 7.2
Var (w) = 0+2^2 Var(x)= 36.96
In the International System of Units (SI), the unit of power is the watt (W), which is equal to one joule per second.
SI unit: watt (W)
In SI base units: kg⋅m2⋅s−3
Card P's balance increased by $3.43 more than Card Q's balance. The accumulated total on Card P over the 4 years is $1080.70 and the accumulated total of Card Q is $1,206.28. Based on the principal outlay however, Card P would have netted a higher interest over Card Q when the principal is subtracted from the accumulated value. (For eg. Card P accumulated value $1080.70 less Principal $726.19 equals $354.51).The interests over the 4 years period would be $354.51 and $351.08 respectively, hence Card P having an increase in balance of $3.43 over Card Q.
