Lewis diagrams of molecules of three different hydrocarbons are shown above. Which of the following claims about the molecules i
s best supported by the diagrams?
1 answer:
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Answer:
a: before equivalence point
b: equivalence point
c: before equivalence point
d: after the eqivalence point
e: before equivalence point
f: after the eqivalence point
Explanation:
Balanced equation of reaction:
NaOH +HCl =NaCl +H2O;
Volume of HCl is fixed and it 100ml and concentration is 1.0M
N1 and N2 normality of HCl and NaOH respectively;
V1 and V2 volume of HCl and NaOH respectively;
we have given molarity but we need normality;
<em>but in case of NaOH and HCl n-factor is 1 for each.</em>
hence
normality=molarity;
At equivalence point:
Before equivalence point :
After the equivalence point:
case a: 5.00 mL of 1.00 M NaOH
hence it is before equivalence point
case b: 100mL of 1.00 M NaOH
hence it is equivalence point
case c: 10.0 mL of 1.00 M NaOH
hence it is before equivalence point
case d: 150 mL of 1.00 M NaOH
hence it is after the eqivalence point
case e: 50.0 mL of 1.00 M NaOH
hence it is before equivalence point
case f: 200 mL of 1.00 M NaOH
hence it is after the eqivalence point
Answer:
Pentane or 2,2-dimethylbutane
Explanation:
I've numbered the isomeric hexanes from 1 to 5 and labelled the sets of equivalent hydrogens.
The results are
Isomer 1— three sets of equivalent hydrogens
Isomer 2— five sets of equivalent hydrogens
Isomer 3— four sets of equivalent hydrogens
Isomer 4— two sets of equivalent hydrogens
Isomer 5— three sets of equivalent hydrogens
Each set will give one monochloro substitution product.
4 = A. Two monochloro isomers.
2 = B. Five monochloro isomers.
3 = C. Four monochloro isomers.
Isomers 1 and 5 each give three monochloro isomers.
Thus, we cannot assign Structure D definitively.
D is either pentane or 2,2-dimethylbutane.
Answer:
p3=0.36atm (partial pressure of NOCl)
Explanation:
2 NO(g) + Cl2(g) ⇌ 2 NOCl(g) Kp = 51
lets assume the partial pressure of NO,Cl2 , and NOCl at eequilibrium are P1 , P2,and P3 respectively
p1=0.125atm;
p2=0.165atm;
p3=?
Kp=51;
On solving;
p3=0.36atm (partial pressure of NOCl)
