Answer:
177.3kg C₂₁H₄₄
Explanation:
Based on the chemical reaction:
C₂₁H₄₄ → 3C₂H₄ + C₁₅H₃₂
<em>Where 1 mole of C₂₁H₄₄ produce 3 moles of ethene, C₂H₄.</em>
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To solve this question we need to determine the moles of ethene in 50.4kg. 1/3 these moles are the moles of C₂₁H₄₄ that must be added:
<em>Moles Ethene -Molar mass: 28.05g/mol-</em>
50.4kg = 50400g * (1mol / 28.05g) = 1796.8 moles of ethene
<em>Moles C₂₁H₄₄:</em>
1796.8 moles of ethene * (1 mol C₂₁H₄₄ / 3 mol C₂H₄) = 589.93 moles C₂₁H₄₄
<em>Mass C₂₁H₄₄:</em>
589.93 moles C₂₁H₄₄ * (296g / mol) = 177283g =
<h3>177.3kg C₂₁H₄₄</h3>
Answer:
A liquid, at any temperature, is in equilibrium with its own steam. This means that on the surface of the liquid or solid substance, there are gaseous molecules of this substance. These molecules exert a pressure on the liquid phase, a pressure known as vapor pressure.
In chemistry, when we talk about dry basis, we talk about a state in which the presence of water in a gaseous state is denied for the calculation. So vapor pressure equals zero.
When we talk about the wet basis, the presence of water in the steam is considered for the calculation, which normally is expressed as a percentage or moisture.
In summary, for a gas mixture steam:
- For dry basis, we just have <em>component A, component B....</em>
- For wet basis, we have <em>water vapor, component A, component B...</em>
So, in wet basis we have an extra component (water).
Assuming we only have 2 components in our steam, and being X the molar fraction of eact component:
- For dry basis: Xa + Xb = 1................................. Xa = 1 - Xb
- For wet basis: Xa + Xb + Xwater = 1 .............Xa = 1 - Xwater - Xb
For dry basis the mole fraction of A it is obtained by subtracting the molar fraction of B from one. And for wet basis, we have to substract the molar fraction of B <u>AND </u>the molar fraction of water vapor. So, logically, the mole fraction Xa will be less for wet basis.
Answer:
A wave reflection interaction (reflected by the wall)
Explanation:
In a reflection, the propagating wave is bounced off the reflecting surface because the medium of the surface prevents the propagation of the wave through it, such that wave is redirected at an angle equal to the angle of incident on the reflecting surface
Reflection takes place with the different forms of waves, such as sound wave, water waves, and light wave
The objects around us are seen with the aid of reflection of light from a light source such that the reflected light enters our eyes after being reflected on the surface of the object, and the object is seen.
I believe the answer is B, or option 2. It makes the most sense, and is a fact.