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4 years ago

Which came the egg or the chiken

Physics

1 answer:

kari74 [83]4 years ago

3 0

Answer:

the chicken.

Explanation:

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A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 420 gram setting. It

natta225 [31]

Answer:

P-value of the test statistic is 2.499

Explanation:

given data:

size sample is 24

sample mean is 414 gm

standard deviation is 15

Null hypotheis is

$H_0: \mu = 420 gm$

$H_1 \mu< 420$

level of significance is 0.01

from test statics

$t = \frac{\hat x - \mu}{\frac{s}{\sqrt{n}}}$

degree od freedom is = n -1

df = 24 -1 = 13

$t = \frac{414 - 420}{\frac{15}{\sqrt{24}}}$

t = -1.959

from t table critical value of t at 0.1 significane level and 23 degree of freedom is 2.499

8 0

3 years ago

PLEASE HELP

Aleksandr [31]

B and C because an earthquake does not directly affect gravity, and precipitation doesn’t fall, it is water surfacing

5 0

3 years ago

You release a pendulum of mass 1 kg from a height of 0.75 m. If there is no air resistance, how fast is the pendulum going when

puteri [66]

Explanation:

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × 9.8 m/s² × 0.75 m)

v = 3.83 m/s

8 0

4 years ago

I need help with this too. (im not good at science or math)

mr_godi [17]

Answer:

i belive 1 m/s

Explanation:

dividing displacement from time it should be 1 cuz 5/5 is 1

please tell me if right!

6 0

3 years ago

Read 2 more answers

An insulating cup contains 200 grams of water at 25 ∘C. Some ice cubes at 0 ∘C is placed in the water. The system comes to equil

Nataly [62]

Answer:

The amount of ice added in gram is 32.77g

Explanation:

This problem bothers on the heat capacity of materials

Given data

Mass of water Mw= 200g

Temperature of water θw= 25°c

Temperature of ice θice= 0°c

Equilibrium Temperature θe= 12°c

Mass of ice Mi=???

The specific heat of ice Ci= 2090 J/(kg ∘C)

specific heat of water Cw = 4186 J/(kg ∘C)

latent heat of the ice to water transition Li= 3.33 x10^5 J/kg

heat heat loss by water = heat gained by ice

N/B let us understand something, heat gained by ice is in two phases

Heat require to melt ice at 0°C to water at 0°C

And the heat required to take water from 0°C to equilibrium temperature

Hence

MwCwΔθ=MiLi +MiCiΔθ

Substituting our data we have

200*4186*(25-12)=Mi*3.3x10^5+

Mi*2090(12-0)

837200*13=Mi*3.3x10^5+Mi*2090

10883600=332090Mi

Mi=10883600/332090

Mi= 32.77g

4 0

4 years ago