A geologist is studying rock layers in an old river bed, and he finds a fossil of a fish and a horsetail rush in the same rock layer. According to the law of faunal and floral succession, the geologist can assume that the rock containing the fossils may date back as far as the <span>Devonian period</span>.
Answer:
α = - 1.883 rev/min²
Explanation:
Given
ωin = 113 rev/min
ωfin = 0 rev/min
t = 1.0 h = 60 min
α = ?
we can use the following equation
ωfin = ωin + α*t ⇒ α = (ωfin - ωin) / t
⇒ α = (0 rev/min - 113 rev/min) / (60 min)
⇒ α = - 1.883 rev/min²
I added individual steps for clarity. Note that g must be positive if the solution is to be real.
![T=2\pi \sqrt{\frac{1}{g}}=2\pi g^{-\frac{1}{2}}\\g^{-\frac{1}{2}} = \frac{T}{2\pi}\\(g^{-\frac{1}{2}})^{-2} = (\frac{T}{2\pi})^{-2}\\g = \frac{4\pi^2}{T^2}\,\,\,, g>0}](https://tex.z-dn.net/?f=T%3D2%5Cpi%20%5Csqrt%7B%5Cfrac%7B1%7D%7Bg%7D%7D%3D2%5Cpi%20g%5E%7B-%5Cfrac%7B1%7D%7B2%7D%7D%5C%5Cg%5E%7B-%5Cfrac%7B1%7D%7B2%7D%7D%20%3D%20%5Cfrac%7BT%7D%7B2%5Cpi%7D%5C%5C%28g%5E%7B-%5Cfrac%7B1%7D%7B2%7D%7D%29%5E%7B-2%7D%20%3D%20%28%5Cfrac%7BT%7D%7B2%5Cpi%7D%29%5E%7B-2%7D%5C%5Cg%20%3D%20%5Cfrac%7B4%5Cpi%5E2%7D%7BT%5E2%7D%5C%2C%5C%2C%5C%2C%2C%20g%3E0%7D)
Let me know if you have any questions.
A table would be the most appropriate because that way you can compare the data.