Question

A disk initially rotated counterclockwise at 1.0 rad/s, but has a counterclockwise angular acceleration of 0.50 rad/s^2 for 2 seconds. After this acceleration, the disk is at an angle of 6.0 rad.
What is the disk’s angular position when the acceleration started?

Answer 1

Answer:

Initial angular position of the disc is 3 radian

Explanation:

As we know that the angular acceleration of the disc is given as

$\alpha = 0.50 rad/s^2$

initial angular speed is given as

$\omega = 1 rad/s$

now we know that angular displacement of the disc is given as

$\theta = \omega t + \frac{1}{2}\alpha t^2$

$\theta = 1(2) + \frac{1}{2}(0.5)(2^2)$

$\theta = 3 rad$

now we have

$\theta_f - \theta_i = 3 rad$

$6 rad - \theta_i = 3$

$\theta_i = 3 ard$