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3 years ago

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Madeline fires a bullet horizontally. The rifle is 1.9 meters above the ground. The bullet travels 200 meters horizontally befor

e it hits the ground. What speed did Madeline's bullet have when it exited the rifle?

1 answer:

Dennis_Churaev [7]3 years ago

7 0

Answer:

322.6 m/s

Explanation:

Given that there are two components of position;

x= vot

y component is;

y= 1.9 - gt^2/2

When the bullet hits the ground, y=0

1.9 -gt^2/2 =0

Where g = 10ms^-2

t= √2 × 1.9/10

t= 0.62 secs

Therefore,

x= vot

vo = x/t

Where, x= 200 m

vo= 200/0.62 =

vo= 322.6 m/s

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<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

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<em>t = time taken (s)</em>

<em>d = distance (m)</em>

Centripetal Acceleration of circular motion could be calculated using following formula:

$\large {\boxed {a_s = v^2 / R} }$

<em>a = centripetal acceleration ( m/s² )</em>

<em>v = velocity ( m/s )</em>

<em>R = radius of circle ( m )</em>

Let us now tackle the problem!

<u>Given:</u>

Radius of horizontal circle = R = 11.0 m

Force Felt by the Trainee = F = 7.80w

<u>Unknown:</u>

Velocity of Rotation = v = ?

<u>Solution:</u>

$F = ma$

$F = m\frac{v^2}{R}$

$7.80w = m\frac{v^2}{R}$

$7.80mg = m\frac{v^2}{R}$

$7.80g = \frac{v^2}{R}$

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$\omega = \frac{29}{2 \pi \times 11.0}$

$\omega \approx 0.42 ~ rev/s$

<h3>Learn more</h3>

Velocity of Runner : brainly.com/question/3813437

Kinetic Energy : brainly.com/question/692781

Acceleration : brainly.com/question/2283922

The Speed of Car : brainly.com/question/568302
Uniform Circular Motion : brainly.com/question/2562955
Trajectory Motion : brainly.com/question/8656387

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Circular Motion

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Circular , Ball , Centripetal

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Answer:

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The acceleration can be found with the kinematic equations

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As we start from rest the initial speed is zero

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Therefore we need the reading of position and time.

Finally, the relationship between the balance reading and this acceleration of the mass of the system

Let's analyze the answers

a) True. It is one of the necessary quantities

b) False. With the equipment we cannot measure the speed directly

c) false. Acceleration is calculated

d) true. It is the other magnitude necessary for the calculation.

The correct answers are a and d

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<h2>Answer:</h2>

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<h2>Explanation:</h2>

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Therefore, the potential energy stored will now be 4 times the original one.

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