A) No, the equations presented above are the product of the derivation of position and velocity when the acceleration is constant.
The equations change to polynomial function of the second degree for the description of the acceleration when described as a function of time.
B) Yes, when the acceleration is zero it is concluded that the velocity is constant, therefore they could be used to describe the position as a function of the change in velocity.
Answer:
(a): emf =
(b): Amplitude of alternating voltage = 20.942 Volts.
Explanation:
<u>Given:</u>
- Area of the coil = A.
- Number of turns of coil = N.
- Magnetic field = B
- Rotation frequency = f.
(a):
The magnetic flux through the coil is given by

where,
= area vector of the coil directed along the normal to the plane of the coil.
= angle between
and
.
Assuming, the direction of magnetic field is along the normal to the plane of the coil initially.
At any time t, the angle which magnetic field makes with the normal to the plane of the coil is 
Therefore, the magnetic flux linked with the coil at any time t is given by

According to Faraday's law of electromagnetic induction, the emf induced in the coil is given by

(b):
The amplitude of the alternating voltage is the maximum value of the emf and emf is maximum when 
Therefore, the amplitude of the alternating voltage is given by

We have,

Putting all these values,

Able to be hammered or pressed permanently out of shape without breaking or cracking.
<span>First of all, the maximum speed occurs when the object passes through the
equilibrium position
The kinetic energy when the object has this max speed is
K= 1/2 * mass * (1.25 m/s)^2
The potential energy in the spring when the speed is equal to zero
U= 1/2 * k * xmax^2
The maximun force of the spring is
mass*acceleration = k*xmax
m * 6.89 m/s2 = k * xmax
xmax = 6.89* m / k
0.5 * m * 1.56 = 0.5 * k * xmax^2
</span>m * 1.56 = k * (<span>6.89* m / k )^2 </span>
<span>
1.56 m = 47.47 m^2 / k
m/k = 0.032862
period = 2 *pi*sqrt[m/k]
= 2 pi </span><span>sqrt [ </span><span>0.032862]
= 1.139 s
A fourth of the period elapses between the instants of max acceleration and maximum speed
= 1/4* period
= 1/4 * </span><span><span>1.139 s </span>
= 0.284s </span>