1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alisha [4.7K]
3 years ago
6

Margaret walks to the store using the following path 0.630 mi west, 0.370 mi north, 0.180 mi east. assume north to be along the

+y-axis and west to be along the -x-axis. what is the magnitude of her total displacement?​
Physics
1 answer:
svp [43]3 years ago
3 0

Answer:

d = 0.583 mi

Explanation:

d = √((-0.630 + 0.180)² + 0.370²)

d = √(-0.450² + 0.370²) = 0.582580... = 0.583 mi

direction would be arctan(0.370/ -0.450) = 39.42780... = 39.4° N of W

You might be interested in
On average, both arms and hands together account for 13 % of a person's mass, while the head is 7.0% and the trunk and legs acco
lianna [129]

Answer:

\dot n_{f} = 85.177\,rpm

Explanation:

The expression for the moment of inertia of the person is:

Arms outstretched

I = \frac{1}{12}\cdot (0.13)\cdot (61\,kg)\cdot (1.40\,m)^{2} + \frac{1}{2}\cdot (0.87)\cdot (61\,kg)\cdot (0.35\,m)^{2}

I = 4.546\,kg\cdot m^{2}

Arms parallel to the trunk

I = \frac{1}{2}\cdot (61\,kg)\cdot (0.35\,m)^{2}

I = 3.736\,kg\cdot m^{2}

The final angular speed is found by means of the Principle of Angular Momentum Conservation:

I_{o}\cdot \dot n_{o} = I_{f}\cdot \dot n_{f}

\dot n_{f} = \frac{I_{o}}{I_{f}}\cdot \dot n_{o}

\dot n_{f} = \left(\frac{4.546\,kg\cdot m^{2}}{3.736\,kg\cdot m^{2}}\right)\cdot (70\,rpm)

\dot n_{f} = 85.177\,rpm

8 0
3 years ago
Is it okay to let children use a phone at dinner? good or not good?
Alex73 [517]
I don’t know it kinda depends really
4 0
4 years ago
Read 2 more answers
if the force of friction is acting on the sliding crate is 100 N how much force will be applied to maintain a constant velocity?
djverab [1.8K]
"Constant velocity" means zero acceleration, which means zero net force.  So there must be100N pulling on the crate to cancel the 100N of friction force.
5 0
4 years ago
A car travelling at 5.0 m/s starts to speed up. After 3.0 s its velocity has increased to 11 m/s. a) What is its acceleration? (
lions [1.4K]

initially, the car is traveling at 5.0 m/s.

so, we know acceleration for changing velocity is :

a = (v-v_{o})/t ..........(i)

where v is the final velocity

v_{o} is the initial velocity

t is the time taken to change velocity

Now, as per the question :

initial velocity, v_{o}=5.0 m/s

final velocity, v =11 m/s

time taken, t = 3 s

putting the values in equation (i),

a = ( 11-5 )/3

a = 2 m/s²

Therefore, a, after 3 s, is  <em>2 m/s².</em>

4 0
1 year ago
Which of the following situations best represents a set of balanced forces?
Deffense [45]

Answer:

A 2 N force pulling and a 10 N force pulling left while a 12N force pulls right.

6 0
3 years ago
Other questions:
  • HELP!!!!!! WILL GIVE BRAINLIEST!!!!!
    5·2 answers
  • The moon appears to rise in the ___ and set in the ___ each day because the Earth rotates ___.
    5·1 answer
  • A coil of self- induction 0.5 H, its ohmic resistance is 10 ⦠carrying a dc current of intensity 2 A, The voltage at its termin
    14·1 answer
  • A 0.32 kg turntable of radius 0.18 m spins about a vertical axis through its center. A constant rotational acceleration causes t
    8·1 answer
  • Speedy Sue, driving at 35.0 m/s, enters a one-lane tunnel. She then observes a slow-moving van 160 m ahead traveling at 5.20 m/s
    12·1 answer
  • A circular metal loop is kept entirely within a magnetic field, but moved to a region of higher field strength while not rotated
    14·1 answer
  • Stellar objects moving away from earth________.
    7·2 answers
  • Proposed Exercise - Circular Movement
    13·1 answer
  • What holds a galaxy together?
    11·2 answers
  • Which of the following materials used by plants to make food can be found in the air?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!