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alisha [4.7K]
3 years ago
6

Margaret walks to the store using the following path 0.630 mi west, 0.370 mi north, 0.180 mi east. assume north to be along the

+y-axis and west to be along the -x-axis. what is the magnitude of her total displacement?​
Physics
1 answer:
svp [43]3 years ago
3 0

Answer:

d = 0.583 mi

Explanation:

d = √((-0.630 + 0.180)² + 0.370²)

d = √(-0.450² + 0.370²) = 0.582580... = 0.583 mi

direction would be arctan(0.370/ -0.450) = 39.42780... = 39.4° N of W

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\theta=53.13^o

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<u>2-D Projectile Motion</u>

In 2-D motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration, while the acceleration in the vertical direction is always the acceleration due to gravity. The basic formulas for this type of movement are

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