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Alex777 [14]
3 years ago
15

ao efetuar a divisão entre dois numeros inteiros positivos, obteve como resultado a dizima periodica 0,57. para obter um numero

natural maior que essa dizima, tem que adicionala a que fração
Mathematics
1 answer:
Ann [662]3 years ago
8 0

Answer:

I will answer in English:

We first have a rational number, the quotient between 2 positive integer numbers is 0.57....

And we want to find which number we should add in order to get 1.

Then we have:

A/B = 0.5757...

So if we have:

x = 0.5757....

we have two periodic decimals, then we multiply by 100 (the number of zeros is equal to the number of periodic decimals)

100*x = 57.575757

Now we subtract the original number:

100*x - x = 99*x = 57.575757... - 0.5757 = 57.

Then we have:

99*0.5757... = 57

0.575757... = 57/99

Now that we know the original fraction, if we want to find a fraction such that:

0.57... + a/b = 1

57/99 + a/b = 1

we should use the same denominator in both fractions:

b = 99

57/99 + a/99 = 1

57 + a = 99

a = 99 - 57 = 42

Then the fraction is 42/99

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Which of the following compositions will map the red figure onto the blue figure?<br> 6lB<br> ATA
melisa1 [442]

Answer:

Point A is translated to A" by T(0, -6), since A has been shifted 6 units down

check the picture, the translated triangle is A"'B"'C"'.

clearly the angle between B"'A"' and B"A"' is 90 degrees, so we can complete the transformation by a 90° clockwise rotation or a 270° counterclockwise rotation.

from the choices given, we see that is is a 270° counterclockwise  rotation.

Answer: A.(o,-6). Ra,270

Read more on Brainly.com - brainly.com/question/4238499#readmore

Step-by-step explanation:

7 0
3 years ago
hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and
Mariulka [41]

Given:

The equation is,

2\log _3x-\log _3(x-2)=2

Explanation:

Simplify the equation by using logarthimic property.

\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{      \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}

Simplify further.

\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}

Solve the quadratic equation for x.

\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

\begin{gathered} x-6=0 \\ x=6 \end{gathered}

For (x - 3) = 0,

\begin{gathered} x-3=0 \\ x=3 \end{gathered}

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0
1 year ago
How many solutions does the system of nonlinear equations graphed below<br> have?
astra-53 [7]

Answer: Look at the number of points where the graphs intersect each other...the points where the graphs of the functions cross each other are the solutions to the system. 

Upon looking, you should see 4 points where the graphs intersect, so there are 4 solutions to the non-linear system of equations. 

Step-by-step explanation:

7 0
3 years ago
How can you use 4s facts to find 7*8
Luda [366]
 
→4(2)  which can be referred to as 4 + 4 

→14 (4)<span>= 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 </span>  which also equal  to → 4  + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 +4 + 4 +4 +4 + 4 +4 +4 
5 0
3 years ago
2x + y = 3<br> x = 2y - 1
Ad libitum [116K]
<span>2x+ y = 3
x = 2y - 1 
Make sure there are NO SPACES in your answer. Include a comma in your answer.
It looks like I could substitute the x=2y-1. Into 2x+y=3
2(2y-1)+y=3
4y-2+y=3
5y=5
y=1
x=2(1)-1
x=1

(1,1)
CHECK
2x+y=3
2(1)+(1)=3
2+1=3
3=3
Left hand side=Right hand side 
Check other equation 
x=2y-1
1=2(1)-1
1=1
Therefore the solution is (1,1). Since the left hand side= right hand side in each equation</span>
8 0
3 years ago
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