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Alex777 [14]
3 years ago
15

ao efetuar a divisão entre dois numeros inteiros positivos, obteve como resultado a dizima periodica 0,57. para obter um numero

natural maior que essa dizima, tem que adicionala a que fração
Mathematics
1 answer:
Ann [662]3 years ago
8 0

Answer:

I will answer in English:

We first have a rational number, the quotient between 2 positive integer numbers is 0.57....

And we want to find which number we should add in order to get 1.

Then we have:

A/B = 0.5757...

So if we have:

x = 0.5757....

we have two periodic decimals, then we multiply by 100 (the number of zeros is equal to the number of periodic decimals)

100*x = 57.575757

Now we subtract the original number:

100*x - x = 99*x = 57.575757... - 0.5757 = 57.

Then we have:

99*0.5757... = 57

0.575757... = 57/99

Now that we know the original fraction, if we want to find a fraction such that:

0.57... + a/b = 1

57/99 + a/b = 1

we should use the same denominator in both fractions:

b = 99

57/99 + a/99 = 1

57 + a = 99

a = 99 - 57 = 42

Then the fraction is 42/99

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5x

Step-by-step explanation:

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2 years ago
6x²-3x+8x-6 Plz do grouping for it
Nat2105 [25]

Answer:

6x^{2} +5x-6

Step-by-step explanation:

Keep 6x^{2} and group -3x+8x which becomes 5x. Then keep -6.

Then it becomes the answer above.

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3 years ago
In the data set below, what are the lower quartile, the median, and the upper quartile?
Studentka2010 [4]

The median, upper and lower quartiles of the data set are:

Lower Quartile = 46

Median = 49

Upper Quartile = 90

<h3>What is the Median?</h3>

The center value or middle value of a data set is the median.

<h3>What are the Upper and Lower Quartiles?</h3>

Upper quartile (Q3) is the center or middle data point of the second half of a data set.

Upper quartile (Q3) is the center or middle data point of the second half of a data set.

Order the data set given as:

32, 46, 49, 49, 77, 90, 96

Lower Quartile = 32, (46), 49, 49, 77, 90, 96 = 46

Median = 32, 46, 49, (49,) 77, 90, 96 = 49

Upper Quartile = 32, 46, 49, 49, 77, (90,) 96 = 90

Learn more about the Median, Upper and Lower Quartiles on:

brainly.com/question/15572643

3 0
2 years ago
A press release describing the 1986 nonstop, round-the-world trip by the aircraft voyager including the following data:
adoni [48]

Answer:

a.) the average speed of the aircraft in miles per hour

115.76 miles/ hour

b.) the fuel consumption in miles per pound of fuel

(assume a density of 0.70 g/mL for the fuel.)

2.8 miles/Ib of fuel

Step-by-step explanation:

A press release describing the 1986 nonstop, round-the-world trip by the aircraft voyager including the following data:

flight distance: 25,012 miles

flight time: 9 days, 3 min., 44 seconds

fuel capacity: nearly 9000 lbs.

fuel remaining at the end of flight: 14 gal.

To the maximum number of significant figure permitted, calculate:

a.) the average speed of the aircraft in miles per hour

Step 1

We convert the time to hours

flight time: 9 days, 3 min., 44 seconds

1 day = 24 hours

9 days =

24 × 9

= 216 hours

60 mins = 1 hour

3 mins =

3/60 = 1/20 = 0.05 hours

1 hour = 60 minutes

1 minute = 60 seconds

1 hour = 60 × 60 = 3600 seconds

If 3600 seconds = 1 hour

44 seconds =

= 44/3600

= 0.0122222222 hours

Total number of hours spent = (216 + 0.05 + 0.0122222222) hours

= 216.06222222 hours

Speed = Distance/Time

= flight distance: 25,012 miles

Speed = 25,012 miles/ 216.06222222hours

= 115.76294895 miles/ hour

Approximately = 115.76 miles/ hour

b.) the fuel consumption in miles per pound of fuel

(assume a density of 0.70 g/mL for the fuel.)

Step 1

We determine how much fuel is used

We have 14 gallons of fuel left over

1 gallon = 3.785 litres

14 gallons =

Cross Multiply

14 gallons × 3.785 liters/1 gallon

= 52.9958 liters

Note that density of fuel =

0.70 g/ml

1 gram / millilitre = 1 kilogram / litre

Hence, 0.7g/ml = 0.7 kg/L

Hence,the mass of fuel left = 52.9958 liters * 0.7 = 37.09706kg

1 kilogram = 2.205 pounds

37.09706kg =

37.09706kg × 2.205 pounds

= 81.7990173 lbs

Since the full capacity = 9000 lbs

The fuel used = 9000 - 81.7990173 lbs

= 8918.2009827 lbs

Hence, fuel consumption is

Distance/ amount of fuel used

25012/8918.2009827 lbs = 2.8046015164 miles/lb of fuel

Approximately = 2.8 miles/Ib of fuel

7 0
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