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4 years ago

How many chromsomes does an elephant egg have?

Chemistry

1 answer:

Artyom0805 [142]4 years ago

7 0

A elephant egg cell has 28 chromosomes.
Both elephant egg and sperm cell make a zygote with 56 chromosomes.

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When the temperature of a reacting mixture increases, the rate of reaction increases. Which statement explains why the rate of r

wlad13 [49]

Answer:

This is one of the factors that affects chemical reactions

Temperature:This is because when the temperature is raised energy in form of heat is supplied to the reacting particles and so the rate of reaction is increased.

3 0

4 years ago

Sodium phosphate and calcium chloride react to form sodium chloride and calcium phosphate. If you have 379.4 grams of calcium ch

GalinKa [24]

Answer:- A. 353.5 g

Solution:- The balanced equation is:

$2Na_3PO_4(aq)+3CaCl_2(aq)\rightarrow 6NaCl(aq)+Ca_3(PO_4)_2(s)$

From this equation, there is 3:1 mol ratio between calcium chloride and calcium phosphate.

Grams of calcium chloride are converted to moles and these moles are multiplied by the mol ratio to get the moles of calcium phosphate. Finally the moles are multiplied by molar mass to get the grams of calcium phosphate.

Molar mass of $CaCl_2$ = 40.078+2(35.45) = 110.978 g per mol

Molar mass of $Ca_3(PO_4)_2$ = 3(40.078)+2(30.974)+8(16.00)

= 120.234+61.948+128.00 = 310.182 g per mol

let's make the set up using dimensional analysis.

$379.4gCaCl_2(\frac{1molCaCl_2}{110.978gCaCl_2})(\frac{1molCa_3(PO_4)_2}{3molCaCl_2})(\frac{310.182gCa_3(PO_4)_2}{1molCa_3(PO_4)_2})$

= $353.5gCa_3(PO_4)_2$

Hence, 353.5 g of calcium phosphate will form and so the correct option is A.

8 0

4 years ago

If the element is closer to the top of the table is it's ionization energy larger?

Ulleksa [173]

Answer:

Explanation:

3 0

3 years ago

What is not produced during glycosis

a_sh-v [17]

The energy containing electron transporters of FADH2 are not produced during glycolysis.

4 0

4 years ago

A reaction A(aq)+B(aq)↽−−⇀C(aq) has a standard free‑energy change of −4.20 kJ/mol at 25 °C. What are the concentrations of A, B,

Dafna1 [17]

Answer : The concentration of $A,B\text{ and }C$ at equilibrium are 0.132 M, 0.232 M and 0.168 M respectively.

Explanation :

The given chemical reaction is,

$A(aq)+B(aq)\rightleftharpoons C(aq)$

First we have to calculate the equilibrium constant for the reaction.

The relation between the equilibrium constant and standard free‑energy is:

$\Delta G^o=-RT \ln k$

where,

$\Delta G^o$ = standard free‑energy change = -4.20 kJ/mole

R = universal gas constant = 8.314 J/mole.K

k = equilibrium constant = ?

T = temperature = $25^oC=273+25=298K$

Now put all the given values in the above relation, we get:

$-4.20kJ/mole=-(8.314J/mole.K)\times (298K) \ln k$

$k=5.45$

Now we have to calculate the concentrations of A, B, and C at equilibrium.

The given equilibrium reaction is,

$A(aq)+B(aq)\rightleftharpoons C(aq)$

Initially 0.30 0.40 0

At equilibrium (0.30-x) (0.40-x) x

The expression of equilibrium constant will be,

$k=\frac{[C]}{[A][B]}$

$5.45=\frac{x}{(0.30-x)\times (0.40-x)}$

By solving the term x, we get

$x=0.168\text{ and }0.716$

From the values of 'x' we conclude that, x = 0.716 can not more than initial concentration. So, the value of 'x' which is equal to 0.716 is not consider.

The value of x will be, 0.168 M

The concentration of $A$ at equilibrium = (0.30-x) = 0.30 - 0.168 = 0.132 M

The concentration of $B$ at equilibrium = (0.40-x) = 0.40 - 0.168 = 0.232 M

The concentration of $C$ at equilibrium = x = 0.168 M

3 0

4 years ago