Answer:
57.2 g
Explanation:
First we <u>convert 66.4 grams of Ba(ClO₄)₂·3H₂O into moles</u>, using its <em>molar mass</em>:
- Molar mass of Ba(ClO₄)₂·3H₂O = Molar mass of Ba(ClO₄)₂ + (Molar Mass of H₂O)*3
 
- Molar mass of Ba(ClO₄)₂·3H₂O = 390.23 g/mol
 
- 66.4 g ÷ 390.23 g/mol = 0.170 mol Ba(ClO₄)₂·3H₂O
 
0.170 moles of Ba(ClO₄)₂·3H₂O would produce 0.170 moles of 0.170 moles of Ba(ClO₄)₂. Meaning we now <u>convert 0.170 moles of Ba(ClO₄)₂ into grams,</u> using the molar mass of Ba(ClO₄)₂:
- 0.170 mol * 336.23 g/mol = 57.2 g
 
 
        
             
        
        
        
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However, I can tell you how to solve this.
Answer:
<span>As the wavelength gets shorter (closer together), the frequency of the wave increases. 
Explanation:
The relation between frequency and wavelength can be described by the help of velocity as follows:
velocity = frequency * wavelength
This means that:
frequency = velocity / wavelength
Noting this equation, we will find that:
The frequency and the wavelength are inversely proportional to each other. This means that as the frequency increases, the wavelength decreases and vice versa.
Now, examining the choices given, we can find that the only statement showing the inverse relation between frequency and wavelength is:
</span><span>As the wavelength gets shorter (closer together), the frequency of the wave increases. 
Hope this helps :)
</span>
        
             
        
        
        
Answer:
pH = 4.27. Porcentaje de disociación: 0.03%
Explanation:
El pH de un ácido débil, HX, se obtiene haciendo uso de su equilibrio:
HX(aq) ⇄ H⁺(aq) + X⁻(aq)
Donde la constante de equilibrio, Ka, es
Ka = 1.65x10⁻⁸ = [H⁺] [X⁻] / [HX]
Como los iones H⁺ y X⁻ vienen del mismo equilibrio podemos decir:
[H⁺] = [X⁻] 
[HX] es:
20g * (1mol/55g) = 0.3636moles / 2.100L = 0.1732M
Reemplazando es Ka:
1.65x10⁻⁸ = [H⁺] [H⁺] / [0.1732M]
2.858x10⁻⁹ = [H⁺]²
5.35x10⁻⁵M = [H⁺]
pH = -log[H⁺]
<h3>pH = 4.27</h3>
El porcentaje de disociacion es [X⁻] / [HX] inicial * 100
Reemplazando
5.35x10⁻⁵M / 0.1732M * 100
<h3>0.03%</h3>
 
        
             
        
        
        
Answer:
 26.981539 u
Atomic number: 13
Symbol: Al
Electron configuration: [Ne] 3s²3p¹