For this case, what we must do is find the scale factor.
We have then that the scale factor is given by:
Where,
L1: side length of polygon ABCD
L2: side length of polygon PQRS
Note: both sides belong to the same side of each polygon
Substituting the values we have:
Rewriting we have:
Answer:
The scale factor of dilation is given by:
Yea i have no clue how she can be like a
Okay so, togo flies 30 miles in 3/5 of an hour with the wind.togo flies 30 miles in 5/6 of an hour against the wind. his rate of speed with the wind was 30 / (3/5) = 30*5/3 = 150/3 = 50 mph.his rate of speed against the wind was 30 / (5/6) = 30*6/5 = 6*6 = 36 mph.3/5 of an hour times 50 mph = 30 miles.
5/6 of an hour times 36 mph = 30 miles.mph looks good.
going he was with the wind.
his rate of speed then was the airplane speed plus the wind speed.coming back he was against the wind.his rate of speed then was the airplane speed minus the wind speed.-----50 mph = A + W36 mph = A - W-----looks like A + W - (A - W) should equal 50 - 36.removing parentheses, equation becomesA + W - A + W = 14.
combining like terms, the equation becomes2*W = 14.dividing both sides by 2, equation becomesW = 7.if W = 7, then A can be found as follows:50 = A + 7A = 43.likewise,36 = A - 7A = 43.since the airplane speed is the same, it looks like the answer is good.solving in the original equations, we get3/5 * (43 + 7) = 303/5 * 50- = 3030 = 30good.-----5/6 * (43 - 7) = 305/6 * 36 = 3030 = 30good.
answer is W = 7 and A = 43.
Answer:
11 9/10
Step-by-step explanation:
6 + 5 = 11
1/10 + 4/5
1/10 + 8/10 = 9/10
11 + 9/10 = 11 9/10
HOPE THIS HELPS
PLZ MARK BRAINLIEST
