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Natalija [7]
2 years ago
13

What volume of 2.0 M sodium phosphate must be used to make 4.0 L of 0.80 M sodium phosphate?

Chemistry
1 answer:
adelina 88 [10]2 years ago
8 0

Answer:

the amount of soduim phosphate is will be 52 percemt

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50 points!! i need 3 answers!!!
tester [92]
Option E, Real gas particles have more complex interactions than ideal gas particles.

In ideal gases, there is absolutely no interaction between any atoms. At all. Atoms simply don't bump into each other in ideal gases.

Obviously, you know that's unrealistic. In real gases, atoms collide into each other all the time.

-T.B.
3 0
2 years ago
Read 2 more answers
Hydrofluoric acid (HF) can be prepared according to the following equation:
Artemon [7]

Given the balanced equation:

( Reaction type : double replacement)

CaF2 + H2SO4 → CaSO4 + 2HFI

We can determine the number of grams prepared from the quantity of 75.0 H2SO4, and 63.0g of CaF2 by converting these grams to moles per substance.

This can be done by evaluating the atomic mass of each element of the substance, and totaling it to find the molecular mass.

For H2SO4 or hydrogen sulfate it's molecular mass is the sum of the quantity of atomic mass per element. H×2 + S×1 + O×4 = ≈1.01×2 + ≈32.06×1 + ≈16×4 = 2.02 + 32.06 + 64 = 98.08 u (Dalton's or Da) or g / mol.

For CaF2 or calcium fluoride, it's molecular mass adds 1 atomic mass of calcium and 2 atomic masses of fluoride due to the number of atoms.

Ca×1 + F×2 = ≈40.07×1 + ≈19×2 = 40.08 + 38 = 78.07 u (Da or Dalton's) or g / mol.

3 0
3 years ago
Read 2 more answers
A hot object will have ___ kinetic energy
Masja [62]

Answer:

More/ Alot? I think is what you are looking for?

Explanation:

It will definitely have some but I'm not sure on what word you are looking for.

6 0
3 years ago
How many moles of xenon gas, Xe, would occopy 37.8L at stp
Charra [1.4K]

Answer:

The number of moles of  xenon are 1.69 mol.

Explanation:

Given data:

Number of moles of xenon = ?

Volume of gas = 37.8 L

Temperature = 273 K

Pressure = 1 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values in formula.

1 atm × 37.8 L = n ×  0.0821 atm.L/ mol.K   ×273 K

37.8 atm.L =  n × 22.413 atm.L/ mol.

n = 37.8 atm.L /  22.413 atm.L/ mol.

n = 1.69 mol

The number of moles of  xenon are 1.69.

8 0
3 years ago
When the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is
gizmo_the_mogwai [7]

Answer : The correct option is, (D) 100 times the original content.

Explanation :

As we are given the pH of the solution change. Now we have to calculate the ratio of the hydronium ion concentration at pH = 5 and pH = 3

As we know that,

pH=-\log [H_3O^+]

The hydronium ion concentration at pH = 5.

5=-\log [H_3O^+]

[H_3O^+]=1\times 10^{-5}M      ..............(1)

The hydronium ion concentration at pH = 3.

3=-\log [H_3O^+]

[H_3O^+]=1\times 10^{-3}M      ................(2)

By dividing the equation 1 and 2 we get the ratio of the hydronium ion concentration.

\frac{[H_3O^+]_{original}}{[H_3O^+]_{final}}=\frac{1\times 10^{-5}}{1\times 10^{-3}}=\frac{1}{100}

100\times [H_3O^+]_{original}=[H_3O^+]_{final}

From this we conclude that when the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is 100 times the original content.

Hence, the correct option is, (D) 100 times the original content.

7 0
3 years ago
Read 2 more answers
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