Answer:
A) 4.035 × 10^(9) J
B) 9.29 × 10^(9) J
Explanation:
We are given;
Capacitance of the original capacitor; C = 1.33 F
Potential difference given to the original capacitor; V = 77.9 kV = 77.9 × 10³ V
A) The formula for Potential energy (U) for the original capacitor is given as:
U = ½CV²
Plugging in the relevant values, we have;
U = ½ × 1.33 × (77.9 × 10³)²
U = 4.035 × 10^(9) J
B) We are told that the capacitor with dielectric constant of 427, was replaced with one possessing a dielectric constant of 983.
Thus;
U = ½ × 1.33 × (983/427) × (77.9 × 10³)²
U = 9.29 × 10^(9) J
Answer:
2800000J
Explanation:
Parameters given:
Mass = 920kg, weight = 920 * 9.8 = 9016N
Distance = 310m
Angle of inclination = 6.5°
Work done is given as :
W = F*d*cosA
Where A = angle of inclination
W = (9016 * 310 * cos6.5)
W = 2776993.59J
In 2 significant figures, W = 2800000J
Answer:
basic quantity. s.I unit. equipment
length M or Cm . metre rule
mass. Kg or G. spring/weight balance
time. Seconds. clock/stopwatch
Temperature. kelvin/celcius thermometer
volume. L/Ml/Cl. measuring cylinder
ANSWER is c
HOPR THIS WILL BE HELPFUL
Answer:
a) dissociates completely
Explanation: strong base is a base that is completely dissociated in an aqueous solution.