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astraxan [27]
3 years ago
10

Which level of organization is formed when a group of organs work together to perform complex functions?

Physics
2 answers:
belka [17]3 years ago
7 0

C) Organ system.

Your organs are working together to control and keep your body moving!! When a organ starts to do they're job it may need some other organs to help. When this happens it begins the Organ System!

Sav [38]3 years ago
4 0

chur answer would be C hope i helped

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An object's position in a given coordinate system is described by the vector r = t2 i - (3t + 3) j. Assume the object moves with
Ipatiy [6.2K]

Answer:

The object´s displacement vector is Δr =  8i - 6 j  

Explanation:

Hi there!

The position vector is given by the following function:

r = t²i - (3t + 3) j

Let´s find the position of the object at time t1 and t2:

At t1 = 1 s:

r1 = (1)² i - (3 · (1) + 3 )j

r1 = 1 i - 6 j

At t2 = 3 s:

r2 = (3)² i - (3 · (3) + 3) j

r2 = 9 i - 12 j

The displacement is calculated as follows:

displacement = Δr = final position - initial position = r2 - r1

r2 - r1 = 9 i - 12 j - (1 i - 6 j)

r2 - r1 = 9 i - 12 j - 1 i + 6 j

r2 - r1 = 8 i - 6 j

The object´s displacement vector is Δr =  8i - 6 j  

8 0
3 years ago
How fast does a 500kg car need to drive to have 100,000 J of kinetic energy?
olchik [2.2K]

Answer:

The car must move at 2 m/s to have a Ke of 2,000 Joules.

Explanation:

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8 0
3 years ago
A drone flies 8 m/s due East with respects to the wind. The wind is blowing 6 m/s due North with respects to the ground. What is
Shalnov [3]

Answer:

v=10 m/s

Explanation:

Given that,

Speed of a drone is 8 m/s due East with respects to the wind

Speed of a drone 6 m/s due North with respect to the ground.

We need to find the speed of the drone with respect to the ground. Let v is the speed. It is given by the resultant of two speeds.

v=\sqrt{8^2+6^2} \\\\v=10\ m/s

So, the speed of the drone with respect to the ground is 10 m/s.

7 0
3 years ago
Write the sequence of filling electrons in the subshell in order of increasing energy.​
tankabanditka [31]

Answer:

In a way of energy “1s” subsell contains most energy. because 1 s subsell contains the electrons of K orbital which is nearest from the nucleus. so the order of energy will be 1s>2s>2p> 3s> 3p> 4s> 3d> 4p> 5s> 4d> 5p> 6s> 4f> 5d> 6p> 7s and the increasing order of thair energies will be- 4s <3d<4p<5s<4d<5p<6s<4f.

5 0
3 years ago
To initiate a nuclear reaction, an experimental nuclear physicist wants to shoot a proton into a 5.50-fm-diameter 12C nucleus. T
Crazy boy [7]

Answer:

The value is  u  =  3.23 *10^{7} \  m/s

Explanation:

From the question we are told that

   The diameter of the nucleus is d =  5.50 \ fm = 5.50 *10^{-15} \  c

   The charge of the proton that makes up the nucleus is  Q_2 = \frac{12}{2}  * 1.60 *10^{-19} =9.6*10^{-19} \ C

    The energy to be impacted is  KE_f  =  2.30 \  MeV  =  2.30 *10^{6} \  eV =   2.30 *10^{6}  *  1.60 *10^{-19} = 3.68*10^{-13} \  J

Generally the radius of the nucleus is mathematically represented as

         r  =  \frac{d}{2}

=>      r  =  \frac{5.50 *10^{-15}}{2}

=>      r  =  2.75 *10^{-15} \  m

Generally from the law energy conservation we have that

     Initial \  total  \  energy \ of the \  proton =  final \  total  \  energy \ of the \  proton

i.e

    T_i  =  T_f

Here

   T_i  =  KE_i + PE_i

Here KE_i is the initial kinetic energy which is mathematically represented as

       KE_I  =  \frac{1}{2}  *  m * u ^2

Here  PE_i is the initial potential energy of the proton and the value is  0 J given that the proton is moving

Also  T_f is mathematically represented as

         T_f  =  KE_f + PE_f

Here  

        PE_f  is the final potential energy which is mathematically represented as

         PE_f  = \frac{k * Q_1 * Q_2}{r}

Here Q_1 is the charge on the proton with a value of Q_1 =  1.60 *10^{-19} \  C

So

        PE_f  = \frac{9*10^{9} *(1.60 *10^{-19} ) * ( 9.6 *10^{-19})}{ 2.75 *10^{-15}}

=>     PE_f  = 5.027 *10^{-13 } \  J

So  

         KE_i + PE_i  =  KE_f + PE_f

=>       \frac{1}{2}  *  m * u ^2 +0  =  3.68*10^{-13} + 5.027 *10^{-13 }

Here m is the mass of the moving proton with value m =  1.67*10^{-27} \  kg

So

       \frac{1}{2}  *  1.67*10^{-27}  * u ^2 +0  =  3.68*10^{-13} + 5.027 *10^{-13 }

=>      u  =  \sqrt{\frac{3.68*10^{-13} + 5.027 *10^{-13 }}{0.5  *  1.67*10^{-27}} }

=>       u  =  3.23 *10^{7} \  m/s

5 0
3 years ago
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