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Arte-miy333 [17]
3 years ago
14

What may be expected when K < 1.0?

Chemistry
2 answers:
Romashka [77]3 years ago
8 0
The reaction will generally form more reactants than products.
IceJOKER [234]3 years ago
8 0

Answer: The concentration of one or more of the products is small.

The reaction will not proceed very far to the right.

The reaction will generally form more reactants than products.

Explanation:

Equilibrium constant is defined as the ratio of concentration of product to the concentration of reactants each raised to the power their stoichiometric ratios. It is represented by the symbol 'K'. For the general equilibrium equation:

aA+bB\rightleftharpoons cC+dD

The expression for equilibrium constant is given as:

K=\frac{[C]^c[D]^d}{[A]^a[B]^b}

There are three cases:  

When K > 1; the reaction is product favored.

When K = 1; the reaction is at equilibrium.

When K < 1; the reaction is reactants favored i.e will shift to left and thus concentration of product is less as compared to concentration of reactant.

Thus, the correct statements are

The concentration of one or more of the products is small.

The reaction will not proceed very far to the right.

The reaction will generally form more reactants than products.

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The awnser is true maybe
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PLEASE! I need help in chemistry. If you are good in chemistry, please send your gm^ail. I have a lab to send. But I am stuck. P
stiv31 [10]

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6 0
3 years ago
What challenges would you encounter with the titration if you had used apple cider vinegar or balsamic vinegar as the analyte in
Vika [28.1K]

Explanation:

Apple cider vinegar or balsamic vinegar might contain various synthetics which might  interact with or nullified the findings, whereas white vinegar comprises of acidic acid only. In fact, apple cider vinegar and balsamic vinegar are deep in appearance this would make it very difficult to determine the color. This is why it is preferable to use white vinegar in the Titration process.

3 0
3 years ago
Iron fluoride (FeF2) dissociates according to the following equation:
melomori [17]

Answer:

S = 0.788 g/L

Explanation:

The solubility product (Kps) is an equilibrium solubization constant, which can be calculated by the equation:

Kps = \frac{[product]^x}{[reagent]^y}

Where x and y are the stoichiometric coefficients of the product and the reagent, respectively. Because of the aggregation form, the concentration of solids is always equal to 1 for use in this equation.

Analyzing the equation, we see that for 1 mol of Fe^{+2} is necessary 2 mols of F^-, so if we call "x" the molar concentration of Fe^2, for F^- we will have 2x, so:

Kps = [Fe^{+2}].[F^-]^2\\\\2.36x10^{-6} = x(2x)^2\\\\2.36x10^{-6} = 4x^3\\\\x^3 = 5.9x10^{-7}\\\\x = \sqrt[3]{5.9x10^{-7}} \\\\x = 8.4x10^{-3} mol/L

So, to calculate the solubility (S) of FeF2, which is in g/L, we multiply this concentration by the molar mass of FeF2, which is:

Fe = 55.8 g/mol

F = 19 g/mol

FeF2 = Fe + 2xF = 55.8 + 2x19 = 93.8 g/mol

So,

[tex]S = 8.4x10^{-3}x93.8

S = 0.788 g/L

4 0
3 years ago
Write balanced chemical equations for the sequence of reactions that oxalic acid can undergo when it's dissolved in water.
Mashcka [7]

Answer and Explanation:

The balanced chemical equations are as follows:

The chemical formula of oxalic is  H_2C_2O_4

In the case when oxalic acts reacted with the water so here the oxalic acid eliminates one proton that leads to the development of mono acids

After that, the second step derives that when oxalic acid is in aqueous solution eliminates other proton so it represent the polyprotic acid

Now the chemical equations are as follows:

Elimination of one proton

H_2C_2O_4(aq)+H_2O(l)  \rightarrow H_2C_2O_4^-(aq) + H_3O^+(aq)

Now the elimination of other proton

HC_2O_4^-(aq)+H_2O(l)  \rightarrow C_2O_4^2^-(aq) + H_3O^+(aq)

7 0
3 years ago
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