What may be expected when K < 1.0?
2 answers:
Answer: The concentration of one or more of the products is small.
The reaction will not proceed very far to the right.
The reaction will generally form more reactants than products.
Explanation:
Equilibrium constant is defined as the ratio of concentration of product to the concentration of reactants each raised to the power their stoichiometric ratios. It is represented by the symbol 'K'. For the general equilibrium equation:
The expression for equilibrium constant is given as:
There are three cases:
When K > 1; the reaction is product favored.
When K = 1; the reaction is at equilibrium.
When K < 1; the reaction is reactants favored i.e will shift to left and thus concentration of product is less as compared to concentration of reactant.
Thus, the correct statements are
The concentration of one or more of the products is small.
The reaction will not proceed very far to the right.
The reaction will generally form more reactants than products.
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Answer: The molar mass of the unknown compound is 200 g/mol
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
i= vant hoff factor = 1 (for molecular compound)
= freezing point constant =
m= molality
Weight of solvent (benzene)= 0.250 kg
Molar mass of solute = M g/mol
Mass of solute = 26.7 g
Thus the molar mass of the unknown compound is 200 g/mol
Schwarzschild Radius here.
So,
The octet rule really only holds up for the second period elements, and only certain elements in that period, for that matter. Elements in the third periods and beyond can have expanded octets.
Draw Lewis dot diagrams for each molecule.
:
P is the central atom bonded individually to each Cl. The only logical diagram is that with three lone pairs surrounding each Cl and the P single-bonded to each Cl atom. If you count the bonds, you will find that P has five pairs, or 10 electrons. This exceeds the octet rule.
:
The Lewis dot diagram for this molecule is a linear molecule with the Be in the center, singly bonded to both F's, each of which have three lone pairs. This means Be has only two pairs, or four electrons. While not an example of a central atom that exceeds the octet rule, Be is one of the special elements that can stably have an incomplete octet.
:
The most stable diagram for this molecule is with S in the center with two lone pairs and singly bonded to each H atom. With four pairs, or 8 electrons, this molecule obeys the octet rule.
:
The diagram for this molecule is C in the center doubly bonded to each O atom. Each O atom has 2 lone pairs. C has four pairs, or 8 electrons. This molecule also obeys the octet rule.
Hope this helps!
So,
The octet rule really only holds up for the second period elements, and only certain elements in that period, for that matter. Elements in the third periods and beyond can have expanded octets.
Draw Lewis dot diagrams for each molecule.
P is the central atom bonded individually to each Cl. The only logical diagram is that with three lone pairs surrounding each Cl and the P single-bonded to each Cl atom. If you count the bonds, you will find that P has five pairs, or 10 electrons. This exceeds the octet rule.
The Lewis dot diagram for this molecule is a linear molecule with the Be in the center, singly bonded to both F's, each of which have three lone pairs. This means Be has only two pairs, or four electrons. While not an example of a central atom that exceeds the octet rule, Be is one of the special elements that can stably have an incomplete octet.
The most stable diagram for this molecule is with S in the center with two lone pairs and singly bonded to each H atom. With four pairs, or 8 electrons, this molecule obeys the octet rule.
The diagram for this molecule is C in the center doubly bonded to each O atom. Each O atom has 2 lone pairs. C has four pairs, or 8 electrons. This molecule also obeys the octet rule.
Hope this helps!