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2 years ago

What may be expected when K < 1.0?

Chemistry

2 answers:

Romashka [77]2 years ago

8 0

The reaction will generally form more reactants than products.

IceJOKER [234]2 years ago

8 0

Answer: The concentration of one or more of the products is small.

The reaction will not proceed very far to the right.

The reaction will generally form more reactants than products.

Explanation:

Equilibrium constant is defined as the ratio of concentration of product to the concentration of reactants each raised to the power their stoichiometric ratios. It is represented by the symbol 'K'. For the general equilibrium equation:

$aA+bB\rightleftharpoons cC+dD$

The expression for equilibrium constant is given as:

$K=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

There are three cases:

When K > 1; the reaction is product favored.

When K = 1; the reaction is at equilibrium.

When K < 1; the reaction is reactants favored i.e will shift to left and thus concentration of product is less as compared to concentration of reactant.

Thus, the correct statements are

The concentration of one or more of the products is small.

The reaction will not proceed very far to the right.

The reaction will generally form more reactants than products.

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How many atoms of mercury are required to produce 3.49 L of H2 gas (density =

Setler79 [48]

The number of mercury atoms required to produce 3.49 L of H2 gas according to the equation would be 1.89 x $10^{23}$

From the balanced equation of the reaction:

$2Hg(l) + 2 HNO_3(aq) ---> Hg_2(NO_3)_2(aq) + H_2(g)$

2 moles of Hg are required to produce 1 mole of the H2 gas.

3.49 L of H2 gas was produced and the density of the gas is 0.0899 g/L

Recall that: density = mass/volume

Mass of the H2 gas = density x volume

= 3.49 x 0.0899

= 0.3138 g of H2 gas

Mole of 0.3138 g of H2 gas = mass/molar mass

= 0.3138/2

= 0.1569 mole

Since the ratio of Hg to H2 according to the equation is 2:1, it means that the mole of Hg is twice the mole of H2.

Thus, mole of Hg = 0.1569 x 2

= 0.3138 mole

According to Avogadro, 1 mole of a substance = 6.022×10^23

0.3138 mole would be:

0.3138 x 6.022 x 10^23

= 1.89 x $10^{23}$

More on the number of atoms in molecules can be found here: brainly.com/question/19036641

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2 years ago

Which statement best relates an empirical formula with a molecular formula?

Elis [28]

Molecular formulas can be determined from empirical formulas.

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3 years ago

How does a multicellular organism develop?

crimeas [40]

Answer:

The cells differentiate.

Explanation:

Organism can be simply classified on the basis of the cellularity of the organism. Two main types of organism are unicellular organisms and the multi cellular organisms.

Multicellular organism contain different types of cells. The different cells differentiate to perform a particular function. The division of labor property is well shown by the multi cellular organism. The cells of the multi cellular organism must show differentiation process.

Thus, the correct answer is option (d).

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2 years ago

How many grams are there in 12.04 x 1024 molecules of H2O2?

Kruka [31]

Answer:

34.01468 grams

Explanation:

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3 years ago

Coal can be used to generate hydrogen gas (a potential fuel) by thefollowing endothermic reaction.C(s) + H2O (g) <==> CO(g

SpyIntel [72]

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

$C(s) + H_2O (g)\leftrightharpoons CO(g) + H_2(g)$

Given that reaction is an endothermic reaction.

For the given options:

a)Adding more C

If the concentration of C that is the reactant is increased, so according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease of concentration of C takes place. Therefore, the equilibrium will shift in the right direction to wards the formation of hydrogen gas.

b) Adding more $H_2O$

If the concentration of water that is the reactant is increased, so according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease of concentration of water takes place. Therefore, the equilibrium will shift in the right direction towards the formation of hydrogen gas.

c) Raising the temperature of the reaction mixture

If the temperature is increased,heat of the equilibrium mixture will also increase so according to the Le-Chatlier's principle , the equilibrium will shift in the direction where decrease in heat that is decrease in temperature occurs.

As, this is an endothermic reaction, forward reaction will decrease the temperature. Hence, the equilibrium will shift in the right direction that is towards the formation of hydrogen gas.

d) Increasing the volume of reaction mixture

If the volume of the container is increased, the pressure will decrease according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where increase in pressure is taking place. As the number of moles of gas molecules is greater at the product side. So, the equilibrium will shift in the right direction that is towards the formation of hydrogen gas.

e) Adding a catalyst to reaction mixture

Role of catalyst is to attain the equilibrium quickly without disturbing the state of equilibrium. Hence, addition of catalyst will not change the equilibrium of the reaction.

f) Adding an inert gas to reaction mixture

Adding inert gas to the mixture at constant volume will not effect the equilibrium. Hence, addition of an inert gas will not change the equilibrium of the reaction.

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3 years ago