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Neko [114]
3 years ago
11

The formula weight of calcium nitrate (ca(no3)2), rounded to one decimal place, is ________ amu. the formula weight of calcium n

itrate (ca(no3)2), rounded to one decimal place, is ________ amu. 204.2 150.1 116.1 164.0 102.1
Chemistry
1 answer:
murzikaleks [220]3 years ago
3 0
<span>164.0 First we must look up the atomic weight of all elements in calcium nitrate Ca: 40.078 N: 14.0067 O: 15.999 Then we compute the mass of the nitrate polyatomic ion which contains one nitrogen and 3 oxygen atoms. 14.0067+3*15.999 = 62.0037 For the entire molecule we calculate the weight of two nitrates and one calcium 2 * 62.0037 + 40.078 = 164.0152 rounding to the tenths place results in 164.0</span>
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Which of the following actions would cause the volume of the chamber below to increase to 36.0 L?
Orlov [11]

Answer:

Option C. Triple the number of moles

Explanation:

From the ideal gas equation:

PV = nRT

Where:

P is the pressure

V is the volume

n is the number of mole

R is the gas constant

T is the absolute temperature.

Making V the subject of the above equation, we have:

PV = nRT

Divide both side by P

V = nRT / P

Thus, we can say that the volume (V) is directly proportional to both the number of mole (n) and absolute temperature (T) and inversely proportional to the pressure (P). This implies that and increase in either the number of mole, the absolute temperature and a decrease in the presence will cause the volume to increase.

Thus, the correct option is option C triple the number of moles. This can further be seen as illustrated below:

Initial volume (V1) = 12 L

Initial mole (n1) = 0.5 mole

Final mole (n2) = triple the initial mole = 3 × 0.5 = 1.5 mole

Final volume (V2) =?

From:

V = nRT / P, keeping T and P constant, we have:

V1/n1 = V2/n2

12/0.5 = V2/1.5

24 = V2/1.5

Cross multiply

V2 = 24 × 1.5

V2 = 36 L.

Thus Option C gives the correct answer to the question.

5 0
3 years ago
Fission and fusion are alike in many ways. However, one difference is
Annette [7]

Explanation:

Fusion vs Fission

In fission, energy is gained by splitting apart heavy atoms, for example uranium, into smaller atoms such as iodine, caesium, strontium, xenon and barium, to name just a few. However, fusion is combining light atoms, for example two hydrogen isotopes, deuterium and tritium, to form the heavier helium. Both reactions release energy which, in a power plant, would be used to boil water to drive a steam generator, thus producing electricity.

4 0
2 years ago
You place a carrot in salt water for 24 hours. What do you observe about the carrot at the end of that time? Choose the two corr
natka813 [3]

Answer:

A & E

Explanation:

Salt water is a hypertonic solution, meaning it extracts water from whatever is placed in it. When a carrot loses water, it will most likely shrivel up and become limp.

8 0
3 years ago
Read 2 more answers
What can be absorbed or produced as the result of a chemical reaction???
tia_tia [17]
Heat can be absorbed or produced
6 0
3 years ago
A pycnometer is a precisely weighted vessel that is used for highly accurate density determinations. Suppose that a pycnometer h
dexar [7]

Answer:

5.758  is the density of the metal ingot in grams per cubic centimeter.

Explanation:

1) Mass of pycnometer = M = 27.60 g

Mass of pycnometer with water ,m= 45.65 g

Density of water at 20 °C = d =998.2 kg/m^3

1 kg = 1000 g

1 m^3=10^6 cm^3

998.2 kg/m^3=\frac{998.2 \times 1000 g}{10^6 cm^3}=0.9982 g/cm^3

Mass of water ,m'= m - M = 45.65 g -  27.60 g =18.05 g

Volume of pycnometer = Volume of water present in it = V

Density=\frac{Mass}{Volume}

V=\frac{m'}{d}=\frac{18.05 g}{0.9982 g/cm^3}=18.08 cm^3

2) Mass of metal , water and pycnometer = 56.83 g

Mass of metal,M' =  9.5 g

Mass of water when metal and water are together ,m''= 56.83 g - M'- M

56.83 g - 9.5 g - 27.60 g = 19.7 g

Volume of water when metal and water are together = v

v=\frac{m''}{d}=\frac{19.7 g}{0.9982 g/cm^3}=19.73 cm^3

Density of metal = d'

Volume of metal = v' =\frac{M'}{d'}

Difference in volume will give volume of metal ingot.

v' = v - V

v'=19.73 cm^3-18.08 cm^3=

v'=1.65 cm^3

Since volume cannot be in negative .

Density of the metal =d'

=d'=\frac{M'}{v'}=\frac{9.5 g}{1.65 cm^3}=5.758 g/cm^3

5 0
3 years ago
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