Answer:
The term reduction means you are reducing the componenets of the air.
Explanation:
Answer:
D
Explanation:
We can use the mole ratio to calculate the partial pressure. The total number of moles is 0.2 + 0.2 + 0.1 = 0.5 moles
Now, we know that the mole fraction of the argon gas would be 0.2/0.5
The partial pressure is as follows. To calculate this, we simple multiply the number of moles by the total pressure.
0.2/0.5 * 5 = 1.0/0.5 = 2.00atm
D
Answer:
1.332 Molar is the molarity of the glucose solution.
Explanation:
Molarity of the solution is the moles of compound in 1 Liter solutions.

Mass of glucose = 60.00 g
Molar mass of glucose = 180.2 g/mol
Volume of the solution = V = 250.0 mL = 0.250 L
(1 mL = 0.001 L)

1.332 Molar is the molarity of the glucose solution.
Answer:
[H₂] = 1.61x10⁻³ M
Explanation:
2H₂S(g) ⇋ 2H₂(g) + S₂(g)
Kc = 9.30x10⁻⁸ = ![\frac{[H_{2}]^2[S_{2}]}{[H_{2}S]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH_%7B2%7D%5D%5E2%5BS_%7B2%7D%5D%7D%7B%5BH_%7B2%7DS%5D%5E2%7D)
First we <u>calculate the initial concentration</u>:
0.45 molH₂S / 3.0L = 0.15 M
The concentrations at equilibrium would be:
[H₂S] = 0.15 - 2x
[H₂] = 2x
[S₂] = x
We <u>put the data in the Kc expression and solve for x</u>:


We make a simplification because x<<< 0.0225:

x = 8.058x10⁻⁴
[H₂] = 2*x = 1.61x10⁻³ M
Answer:
Helium and Ethlyene Oxide. Your answer is MASS.
Explanation:
Diffusion is faster at higher temperatures because the gas molecules have greater kinetic energy. effusion refers to the movement of gas particles through a small hole. Graham's law state's that the effusion rate of a gas is inversely proportional to the square root of the mass of its particles.