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3 years ago

In the balanced equation, 4KO2 + 2CO2 = 2K2CO3 + 3O2 which two chemicals have a molar ratio of 3:4?

Chemistry

2 answers:

Sveta_85 [38]3 years ago

3 0

4KO₂ + 2CO₂ → 2K₂CO₃ + 3 O₂

The two chemicals that have a molar ratio of 3:4 is in equation above O₂ and KO₂

<em><u>explanation</u></em>

The molar ratio is the ratio between the amount in moles of two compounds that are involved in a chemical reaction.

In the equation above the mole ratio is determined by examining coefficient ( <em>number in front of the formula</em>)

the coefficient of O₂ is 3 while that of KO₂ is 4 therefore the mole ratio of O₂:KO₂ is 3:4

Jobisdone [24]3 years ago

3 0

Answer:

Oxygen gas and potassium superoxide have a molar ratio of 3:4.

Explanation:

$4KO_2 + 2CO_2\rightarrow 2K_2CO_3 + 3O_2$

According to reaction, 4 moles of potassium superoxide reacts with 2 moles of carbon dioxide to give 2 moles of potassium carbonate and 3 moles of oxygen gas.

Mole ratio is defined as ratio of moles of two chemical compounds in a given chemical equation of the reaction.

Moles of potassium superoxide = 4

Moles of carbon dioxide = 2

Moles of potassium carbonate = 2

Moles of oxygen gas = 3

Molar ratio of oxygen to potassium superoxide = $\frac{3 mol}{4 mol}=\frac{3}{4}$

Oxygen gas and potassium superoxide have a molar ratio of 3:4.

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Enter your answer in the provided box. When mixed, solutions of barium chloride, BaCl2, and potassium chromate, K2CrO4, form a y

ira [324]

Answer:

35.42g

Explanation:

Step 1:

The balanced equation for the reaction

BaCl2(aq) + K2CrO4(aq) → BaCrO4(s) + 2KCl(aq)

Step 2:

Determination of the limiting reactant.

It is important to determine which of the reactant is limiting the reaction as the limiting reactant is used to determine the maximum yield of the reaction. The limiting reactant can be determined as follow:

From the balanced equation above,

1 mole of BaCl2 reacted with 1 mole of K2CrO4.

Therefore, 0.7 mole of BaCl2 will also react with 0.7 mol of K2CrO4.

From the above illustration, we can see that it requires a higher amount of K2CrO4 to react with 0.7 mol of BaCl2. This simply means that K2CrO4 is the limiting reactant.

Step 3:

Determination of the number of mole of BaCrO4 produced from the reaction.

The limiting reactant is used in this case.

From the balanced equation above,

1 mole of K2CrO4 produced 1 mole of BaCrO4.

Therefore, 0.14 mole of K2CrO4 will also produce 0.14 mole of BaCrO4.

Step 4:

Converting 0.14 mole of BaCrO4 to grams.

This is illustrated below:

Molar Mass of BaCrO4 = 137 + 52 + (16x4) = 137 + 52 + 64 = 253g/mol

Number of mole BaCrO4 = 0.14 mole

Mass of BaCrO4 =?

Mass = number of mole x molar Mass

Mass of BaCrO4 = 0.14 x 253

Mass of BaCrO4 = 35.42g

Therefore, 35.42g of BaCrO4 is produced from the reaction.

4 0

3 years ago

a student determined that it requires 106220 j of energy to vaporize 47g of water. is the student is right

shusha [124]

<h2>Answer:</h2>

He is right that the energy of vaporization of 47 g of water s 106222 j.

<h3>Explanation:</h3>

Enthalpy of vaporization or heat of vaporization is the amount of energy which is used to transform one mole of liquid into gas.

In case of water it is 40.65 KJ/mol. And 18 g of water is equal to one mole.

It means for vaporizing 18 g, 40.65 kJ energy is needed.

So for energy 47 g of water = 47/18 * 40.65 = 106.1 KJ

Hence the student is right about the energy of vaporization of 47 g of water.

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3 years ago

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Lelu [443]

A) B). That’s it I hope it’s help.

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2 years ago

You come home and find that there's been a power outage while food was cooking in the slow cooker. What should you do wit the fo

klasskru [66]

Answer:

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Explanation:

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3 years ago

Students find the pH of Substance A to be 2.1 and Substance B to be 4.4. They are told Substance C is less acidic than Substance

Slav-nsk [51]

Answer:

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Explanation:

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3 years ago