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leva [86]
3 years ago
12

In the balanced equation, 4KO2 + 2CO2 = 2K2CO3 + 3O2 which two chemicals have a molar ratio of 3:4?

Chemistry
2 answers:
Sveta_85 [38]3 years ago
3 0

 4KO₂  + 2CO₂  →    2K₂CO₃  + 3 O₂

The two  chemicals  that  have a  molar ratio  of 3:4   is  in equation above O₂   and KO₂

<em><u>explanation</u></em>

The molar ratio  is the ratio  between  the amount in moles  of two  compounds  that are involved  in a chemical reaction.

In the  equation above the mole  ratio  is determined  by examining coefficient ( <em>number in front of the formula</em>)


the coefficient of O₂  is 3 while that of KO₂ is 4  therefore the  mole ratio of O₂:KO₂  is 3:4


Jobisdone [24]3 years ago
3 0

Answer:

Oxygen gas and potassium superoxide have a molar ratio of 3:4.

Explanation:

4KO_2 + 2CO_2\rightarrow 2K_2CO_3 + 3O_2

According to reaction, 4 moles of potassium superoxide reacts with 2 moles of carbon dioxide to give 2 moles of potassium carbonate and 3 moles of oxygen gas.

Mole ratio is defined as ratio of moles of two chemical compounds in a given chemical equation of the reaction.

Moles of potassium superoxide = 4

Moles of carbon dioxide = 2

Moles of potassium carbonate = 2

Moles of oxygen gas = 3

Molar ratio of oxygen to potassium superoxide = \frac{3 mol}{4 mol}=\frac{3}{4}

Oxygen gas and potassium superoxide have a molar ratio of 3:4.

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<u>Answer:</u> The mass of nickel that was originally heated is 28.4 grams.

<u>Explanation:</u>

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]       ......(1)

where,

q = heat absorbed or released

m_1 = mass of nickel = ?

m_2 = mass of water = 150.0 g

T_{final} = final temperature = 25.0°C

T_1 = initial temperature of nickel = 99.8°C

T_2 = initial temperature of water = 23.5°C

c_1 = specific heat of nickel = 0.444 J/g°C

c_2 = specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

m_1\times 0.444\times (25.0-99.8)=-[150.0\times 4.186\times (25.0-23.5)]

m_1=28.4g

Hence, the mass of nickel that was originally heated is 28.4 grams.

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