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leva [86]
3 years ago
12

In the balanced equation, 4KO2 + 2CO2 = 2K2CO3 + 3O2 which two chemicals have a molar ratio of 3:4?

Chemistry
2 answers:
Sveta_85 [38]3 years ago
3 0

 4KO₂  + 2CO₂  →    2K₂CO₃  + 3 O₂

The two  chemicals  that  have a  molar ratio  of 3:4   is  in equation above O₂   and KO₂

<em><u>explanation</u></em>

The molar ratio  is the ratio  between  the amount in moles  of two  compounds  that are involved  in a chemical reaction.

In the  equation above the mole  ratio  is determined  by examining coefficient ( <em>number in front of the formula</em>)


the coefficient of O₂  is 3 while that of KO₂ is 4  therefore the  mole ratio of O₂:KO₂  is 3:4


Jobisdone [24]3 years ago
3 0

Answer:

Oxygen gas and potassium superoxide have a molar ratio of 3:4.

Explanation:

4KO_2 + 2CO_2\rightarrow 2K_2CO_3 + 3O_2

According to reaction, 4 moles of potassium superoxide reacts with 2 moles of carbon dioxide to give 2 moles of potassium carbonate and 3 moles of oxygen gas.

Mole ratio is defined as ratio of moles of two chemical compounds in a given chemical equation of the reaction.

Moles of potassium superoxide = 4

Moles of carbon dioxide = 2

Moles of potassium carbonate = 2

Moles of oxygen gas = 3

Molar ratio of oxygen to potassium superoxide = \frac{3 mol}{4 mol}=\frac{3}{4}

Oxygen gas and potassium superoxide have a molar ratio of 3:4.

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A mixture of ethyl acetate vapour and air has a relative saturation of 50% at 303 K and a total pressure of 100 kPa. If the vapo
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Explanation :

The formula used for relative saturation is:

\text{Relative saturation}=\frac{P_A}{P_A^o}

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P_A^o = vapor pressure of ethyl acetate

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Now we have to calculate the molar saturation.

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P(vapor free) = 100 kPa - 8 kPa = 92 kPa

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