C. marbles placed inside hollow sphere
Answer:
Deep inside Earth, between the molten iron core and the thin crust at the surface, there is a solid body of rock called the mantle. When rock from the mantle melts, moves to the surface through the crust, and releases pent-up gases, volcanoes erupt.
Explanation: hot molten rock, ash, and gases escape from the volcano
Answer:
V₂ → 106.6 mL
Explanation:
We apply the Ideal Gases Law to solve the problem. For the two situations:
P . V = n . R . T
Moles are still the same so → P. V / R. T = n
As R is a constant, the formula to solve this is: P . V / T
P₁ . V₁ / T₁ = P₂ .V₂ / T₂ Let's replace data:
(1.20 atm . 73mL) / 112°C = (0.55 atm . V₂) / 75°C
((87.6 mL.atm) / 112°C) . 75°C = 0.55 atm . V₂
58.66 mL.atm = 0.55 atm . V₂
58.66 mL.atm / 0.55 atm = V₂ → 106.6 mL
Answer:
3.14 grams of ammonium thiocyanate must be used to react completely with 6.5 g barium hydroxide octahydrate.
Explanation:
![Ba(OH)_2.8H_2O(s)+NH_4SCN(s)\rightarrow Ba(SCN)_2(s)+8H_2O(l)+NH_3(g)](https://tex.z-dn.net/?f=Ba%28OH%29_2.8H_2O%28s%29%2BNH_4SCN%28s%29%5Crightarrow%20Ba%28SCN%29_2%28s%29%2B8H_2O%28l%29%2BNH_3%28g%29)
The balance chemical equation is :
![Ba(OH)_2.8H_2O(s)+2NH_4SCN(s)\rightarrow Ba(SCN)_2(s)+10H_2O(l)+2NH_3(g)](https://tex.z-dn.net/?f=Ba%28OH%29_2.8H_2O%28s%29%2B2NH_4SCN%28s%29%5Crightarrow%20Ba%28SCN%29_2%28s%29%2B10H_2O%28l%29%2B2NH_3%28g%29)
Mass of barium hydroxide octahydrate = 6.5 g
Moles of barium hydroxide octahydrate = ![\frac{6.5 g}{315 g/mol}=0.020635 mol](https://tex.z-dn.net/?f=%5Cfrac%7B6.5%20g%7D%7B315%20g%2Fmol%7D%3D0.020635%20mol)
According to reaction, 2 moles of ammonium thiocyanate reacts with1 mole of barium hydroxide octahydrate. The 0.020635 moles of barium hydroxide octahydrate will react with:
![\frac{2}{1}\times 0.020635 mol=0.04127 mol](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B1%7D%5Ctimes%200.020635%20mol%3D0.04127%20mol)
Mass of 0.04127 moles of ammonium thiocyanate;
![0.04127 mol\times 76 g/mol=3.136 g\approx 3.14 g](https://tex.z-dn.net/?f=0.04127%20mol%5Ctimes%2076%20g%2Fmol%3D3.136%20g%5Capprox%203.14%20g)
3.14 grams of ammonium thiocyanate must be used to react completely with 6.5 g barium hydroxide octahydrate
Answer:
0.68
Explanation:
Number of moles is directly propotionalto the volume at standard condition.