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lys-0071 [83]
3 years ago
10

Indicate whether each statement is true or false: a. Substitutional alloys tend to be more ductile than interstitial alloys. b.

Interstitial alloys tend to form between elements with similar ionic radii. c. Nonmetallic elements are never found in alloys.
Chemistry
1 answer:
Masteriza [31]3 years ago
3 0

Answer:

Substitutional alloys tend to be more ductile than interstitial alloys. true

Interstitial alloys tend to form between elements with similar ionic radii.false

Nonmetallic elements are never found in alloys. false

Explanation:

Substitutional alloys consists components having similar atomic(ionic) radii as well as common bonding characteristics. In interstitial alloys, atoms in interstitial positions must have a much smaller covalent radius than the solvent atoms. Interstitial atoms are generally less ductile than substitutional alloys.

Nonmetals are found in alloys. For instance, carbon is a component of the common alloy called steel.

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I would say developed technologies which somehow were lost

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calculate pressure exerted by 1.255 mol of CI2 in a volume of 5.005 L at a temperature 273.5 k using ideal gas equation
balu736 [363]

Answer:

The pressure is 5.62 atm.

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case:

  • P= ?
  • V= 5.005 L
  • n= 1.255 mol
  • R= 0.082 \frac{atm*L}{mol*K}
  • T= 273.5 K

Replacing:

P* 5.005 L= 1.255 mol* 0.082 \frac{atm*L}{mol*K} *273.5 K

Solving:

P=\frac{1.255 mol* 0.082 \frac{atm*L}{mol*K} *273.5 K}{5.005 L}

P= 5.62 atm

<u><em>The pressure is 5.62 atm.</em></u>

8 0
3 years ago
Please answer this questions soon<br><br>i will mark him or her brillient<br>​
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Answer:

1)Or

d.Sublimation

2)

b.iodine is the solute and alcohol is solvent

3)

a.compostion of solute

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Finding the pH for [H+] = 9.4 * 10-3 M?
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Answer:

pH = 2.0

Explanation:

To find the pH of a solution, take the -log[H+]. In this case, the -log(9.4 x 10^-3) equals 2.02687 which makes 2.0 when accounting for significant figures.

3 0
3 years ago
How much energy is used to melt 44.33 g of solid oxygen?
Nutka1998 [239]

Answer:

Q1 = C * m * dT

Q2 = Qm * m

Qtotal = Q1 + Q2

Q1 - is amount of energy you need to apply to heat oxygen from the current temperature till you reach the melting temperature. Only if the oxygen is below to melting temperature.

C - is calorific capacity of oxygen -- better look at tables, it is a constant value

m - is the amount of oxygen, we will use moles because the other data shows moles, but could be grams, kg, etc.

dT - is the diference of temperatures between the current and the melting one. The melting temperature is constant and you can find it on tables, then (Tm - To)

Q2 is the amount of energy you have to add to melt oxygen once the oxygen has reached the melting temperature (Tm)

Qm is a constant value you could find on tables, depends on the mass of oxygen and is due to internal processes as changes in atomic distributions

If the oxygen is initially at melting temperature (melting point) you only need to know Q2, as dT = 0

I will do an example for you, but in future you should provide data of constants, it takes very long to find them in books or internet.

Data from tables

Tm =  54.36 K

C = 29.378 J/mol K this is at 25 C (or 298 K), is not really correct, you should look at its value at less than 54.36 K, but you can use it here.

Qm = 0.444 kJ/mol

Problem -- you have 44.33g of Oxygen -- Molecular weight of O2 is 32 g/mol

So you have 44.33/32 = 1.385 moles of oxygen

a) if oxygen is already at melting temperature: you only have to melt it

Qtotal = Q1 + Q2 = [0 (dT = 0) + Qm * m] = 0.444 * 1.385 = 0.615 kJ = 615 J

b) supposing an initial temperture of 50 K: now you have to heat oxygen till melting temperature and then melt it.

Q1 = C * m * dT = 29.378 * 1.385 * (54.36 - 50) = 177.442 J

Q2 = Qm * m = 615 J

Qtotal = 177.442 + 615 = 792.44 J

Explanation:

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