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3 years ago

14

What three types of Protists have been discovered

2 answers:

frosja888 [35]3 years ago

8 0

Answer:

the answer is D

Explanation:

but hope this helps

Musya8 [376]3 years ago

7 0

Answer:

Yo, wassup I think its D.

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Why do scientists use computer programs to model protein structure and function

Serjik [45]

It's because proteins are very small and hard to see.

4 0

3 years ago

Why is the melting point of a network solid so high? How is this related to what a network solid is?

Alexxandr [17]

I believe that the answer to the question provided above is that molecules in solid are compact and are connected. It requires huge energy to move it, thus requires high temperature.
Hope my answer would be a great help for you. If you have more questions feel free to ask here at Brainly.

4 0

3 years ago

In a hospital laboratory, a 10.0 mL sample of gastric juice (predominantly HCl), obtained several hours after a meal, was titrat

LiRa [457]

Answer: 1.14

Explanation:

$HCl+NaOH\rightarrow NaCl+H_2O$

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1M\\V_2=7.2mL$

Putting values in above equation, we get:

$1\times M_1\times 10.0=1\times 0.1\times 7.2\\\\M_1=0.072M$

To calculate pH of gastric juice:

molarity of $H^+$ = 0.072

$pH=-log[H^+]$

$pH=-log(0.072)=1.14$

Thus the pH of the gastric juice is 1.14

3 0

3 years ago

when the sum 4.9965 + 2.11 + 3.887 is calculated, to how many decimal places should the answer be reported?

jarptica [38.1K]

Answer:

the correct answer is four decimal places

3 0

3 years ago

How many moles are in 2.5L of 1.75 M Na2CO3

mixas84 [53]

Answer: There are 4.375 moles in 2.5 L of 1.75 M $Na_2CO_3$

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of solution = 1.75 M

Volume of solution = 2.5 L

Putting values in equation , we get:

$1.75M=\frac{\text{Moles of} Na_2CO_3}{2.5L}\\\\\text{Moles of }Na_2CO_3=1.75mol/L\times 2.5L=4.375mol$

6 0

2 years ago