The cloud with those characteristics is #1
Answer:
1) After adding 15.0 mL of the HCl solution, the mixture is before the equivalence point on the titration curve.
2) The pH of the solution after adding HCl is 12.6
Explanation:
10.0 mL of 0.25 M NaOH(aq) react with 15.0 mL of 0.10 M HCl(aq). Let's calculate the moles of each reactant.


There is an excess of NaOH so the mixture is before the equivalence point. When HCl completely reacts, we can calculate the moles in excess of NaOH.
NaOH + HCl ⇒ NaCl + H₂O
Initial 2.5 × 10⁻³ 1.5 × 10⁻³ 0 0
Reaction -1.5 × 10⁻³ -1.5 × 10⁻³ 1.5 × 10⁻³ 1.5 × 10⁻³
Final 1.0 × 10⁻³ 0 1.5 × 10⁻³ 1.5 × 10⁻³
The concentration of NaOH is:
![[NaOH]=\frac{1.0 \times 10^{-3} mol }{25.0 \times 10^{-3} L} =0.040M](https://tex.z-dn.net/?f=%5BNaOH%5D%3D%5Cfrac%7B1.0%20%5Ctimes%2010%5E%7B-3%7D%20mol%20%7D%7B25.0%20%5Ctimes%2010%5E%7B-3%7D%20L%7D%20%3D0.040M)
NaOH is a strong base so [OH⁻] = [NaOH].
Finally, we can calculate pOH and pH.
pOH = -log [OH⁻] = -log 0.040 = 1.4
pH = 14 - pOH = 14 - 1.4 = 12.6
<h2>In the name, iron(III) oxide, the (III) represents: D) the electrical charge of iron</h2><h2>
Explanation:</h2>
To attain stability the chemical bond is formed .
Chemical bond
It is a kind of linkage that binds one atom with the other .
The atoms do so in order to attain stable noble gas configuration .
To form chemical bond they either:
Loose electrons : when atoms loose electrons they acquire positive charge which is equal to the number of electrons lost .
Gain electrons: After gaining electrons they acquire negative charge which is equal to the number of electrons gained by an atom.
share electrons : With sharing no charges are develop .
<em>In the above asked question when iron combines with oxygen it forms iron oxide : where iron looses 3 electrons and oxygen gains 2 electrons .That is the reason ,III here represents the electrical charge of iron</em>
The atomic number is always equal to the number of protons. It will be equal to the number of elections also if the atom has a neutral charge.
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Explanation:
Element Abundance percent by weight Abundance parts per million by weight
Oxygen 46.1% 461,000
Silicon 28.2% 282,000
Aluminum 8.23% 82,300
Iron 5.63% 56,300